Answer:
The variable x lies within the interval of all positive real numbers less than 5 cm.
Detailed solution:
Problem statement:
Determine the volume of the open-topped box as a function of the side length x (in centimeters) of the square cutouts.
Refer to the provided diagram for clarity.
Define:
x → length in centimeters of each square cutout side
The volume of the box with open top can be written as:
Given this, we have:
By substitution:
Determine the domain of x:
Because:
Therefore:
Domain is the interval (0,5)
That means all real numbers strictly greater than zero and less than 5 cm are valid for x.
Hence, the volume V as a function of x is:
Answer: (3y - 5) • (2y - 3)
Step-by-step explanation: 6y2 - 10y - 9y - 15
2.1 Factoring 6y2-19y+15
The leading term is 6y2, with a coefficient of 6.
The middle term is -19y, having a coefficient of -19.
The last term is the constant, which is +15.
Response:
2/9 = 0.22
Clarification:
There are two ways to select the first number that is odd and less than 5: 1 and 3.
For each of these, the second number drawn can be any of the values from 1 to 9, giving us a total of 18 options.
Out of these, the only pairs that result in a sum less than 5 are (1,1), (1,2), (1,3), and (3,1). Thus we have 4 combinations from the total of 18:
4/18 = 2/9 = 0.22
The formula for the volume of a sphere can be derived as follows. We will approach this through calculus, utilizing the concept of a solid of revolution; this is a three-dimensional shape formed by rotating a two-dimensional curve around a straight line (the axis of revolution) that lies within the same plane. From calculus, we know that we will generate a shape by rotating the specified circumference. Next, we isolate y and utilize certain limits for this integral.
Every square meter of ceiling needs 10.75 tiles. To calculate the number of tiles needed for various ceiling areas: For a ceiling area of 1, it requires 10.75 tiles. For a ceiling area of 10, it requires 10.75 × 10, which equals 107.5 tiles. For an area of 100, it needs 10.75 × 100, totaling 1075 tiles. Consequently, that represents the necessary solution.
