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kap26
11 days ago
5

Desert Dunes High School has two mathematics classes for each year. One class is a standard class containing students who posses

s standard mathematical ability. The other class is an advanced class containing the all-round brightest students in each year. Due to time tabling issues at the school, the students in the advanced class are selected based on their abilities in both English and mathematics (thus forming two advanced classes in one).
The grades obtained by students in the standard mathematics class range from very low to very high. Most students gain marks between 60% and 70%, with an average mark of 65%. On rare occasions a student may severely fail, in which case this student is kept back a year. On similarly rare occasions a student may obtain a mark of over 90%, in which case this student is moved up to the advanced class.

The grades obtained by students in the advanced class vary substantially between those students who are in the class because of their mathematical ability and those who are in the class because of their English ability. Most of the mathematically inclined students gain marks between 90% and 100%, with an average of 95%. Most of the students who are talented at English gain marks between 50% and 60%, with an average of 55%.

Out of the standard and advanced classes, it would be more reasonable to model the grades of the ADVANCED or STANDARD mathematics class with a normal distribution????
Mathematics
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Answer:

a) 0.216

b) 0.784

c) 0.288

d) 0.352

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Step-by-step explanation:

The steps for solving this are provided in an image.

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2 months ago
What is the fewest number of points you must plot in order to have examples of all four sets of​ numbers, including at least one
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Let’s outline the sets:

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Thus:

2 qualifies as a:

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Since 2 is positive and an integer, it falls into the category of natural numbers.

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If we include a negative example, we can consider -3.

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3 months ago
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Answer: P(\text{a ticket is randomly chosen will award a large prize)}=\frac{2}{21}

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\text {Possibility of getting a winning ticket }=^{10}C_6

For every three prizes, there’s one large prize

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\text{ Possibility of getting a large prize }=^6C_3

At this point,

P(\text{a ticket is randomly chosen will award a large prize)}=\frac{^6C_3}{^{10}C_6}\\\\=\frac{20}{210}\\\\=\frac{2}{21}

P(\text{a ticket is randomly chosen will award a large prize)}=\frac{2}{21}

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2 months ago
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