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vesna_86
15 days ago
8

Q3: Summation Write a recursive implementation of summation, which takes a positive integer n and a function term. It applies te

rm to every number from 1 to n including n and returns the sum of the results. # Question 3 def summation(n, term) : ""Return the sum of the first n terms in the sequence defined by term. Implement using recursion! >>> summation(5, lambda x: x * x * x) # 1^3 + 2^3 + 3^3 + 4^3 + 5^3 225 >>> summation(9, lambda x: x + 1) # 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 54 >>> summation(5, lambda x: 2**x) # 241 + 2^2 + 2^3 + 2^4 + 245 62 >>> # Do not use while for loops!

Engineering
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. Were you able to observe ???? = 0 in the circuit you constructed during lab? Why or why not? Hint: What value of resistance wo
Mrrafil [318]

Answer:

An attachment follows below

Explanation:

1) The formula used for the damping coefficient in a series RLC circuit.

If \xi = 0, it is possible to set c = 0 but an inductor will still possess some capacitance.

2) The behaviors of critically damped and underdamped systems are illustrated along with comments on their temporal responses.

4) While several answers might suffice, the four I’ve highlighted are the crucial parameters necessary about an unknown op-amp before utilizing it in a circuit.

Hope this addresses all your inquiries.

5 0
3 months ago
A well-insulated rigid tank contains 1.5 kg of a saturated liquid–vapor mixture of water at 200 kPa. Initially, three-quarters o
Daniel [329]

Answer:

The change in entropy of the steam is 2.673 kJ/K

Explanation:

The mass of the liquid-vapor mixture is 1.5 kg

The mass in the liquid phase is calculated as 3/4 × 1.5 kg = 1.125 kg

The mass in the vapor phase is calculated as 1.5 - 1.125 = 0.375 kg

According to the steam tables

At a pressure of 200 kPa (200/100 = 2 bar), the specific entropy of steam is found to be 7.127 kJ/kgK

The entropy of steam can be calculated as specific entropy multiplied by mass = 7.127 × 0.375 = 2.673 kJ/K

6 0
3 months ago
Read 2 more answers
A 5-cm-diameter shaft rotates at 4500 rpm in a 15-cmlong, 8-cm-outer-diameter cast iron bearing (k = 70 W/m·K) with a uniform cl
Kisachek [356]

Answer:

(a) the rate of heat transfer to the coolant is Q = 139.71W

(b) the surface temperature of the shaft T = 40.97°C

(c) the mechanical power wasted by the viscous dissipation in oil 22.2kW

Explanation:

See explanation in the attached files

5 0
2 months ago
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