A mechanical system comprises three subsystems in series with reliabilities of 98, 96, and 94 percent. What is the overall relia

Compute the sum with carry-wraparound (sometimes called the one's complement sum) of the following two numbers. Give answer in 8

grin007 [323]

Response:

00100111

Explanation:

We have been given;

10010110

10010000

Add them following standard binary addition rules

10010110

10010000

-------------

(1)00100110

-------------

ignore the leading (1) because it is a carry.

Increase the result by 1 to achieve a 1's complement sum

00100110 + 1 = 00100111

Final Result: 00100111

3 0

2 months ago

___________ is NOT a common injury that an automotive tech may experience at work.

Viktor [391]

Answer: The most frequently occurring injuries were sprains/strains, accounting for 39% of the total; lacerations comprised 22%, and contusions represented 15%. Almost half (49%) of the injuries led to one or more days of lost or restricted work; 25% resulted in 7 or more days lost or restricted.

Explanation:

Sprains/strains were the predominant injuries happening, making up 39% of all cases, while lacerations followed at 22% and contusions at 15%. Of these injuries, 49% caused employees to miss or face restricted workdays, with 25% leading to a minimum of 7 days lost or restricted.

7 0

3 months ago

The manufacturer of a 1.5 V D flashlight battery says that the battery will deliver 9 mA for 40 continuous hours. During that ti

pantera1 [306]

Response:

a) 144.000 seconds

b) and c) Battery voltage and power graphs are in the attached image.

$V=-\frac{0.5}{144000} t + 1.5 V[tex] [tex]P(t)=-(31.25X10^{-9}) t+0.0135$ where D:{0<t h="" />

d) 1620 J

Description:

a) The initial response is derived via a rule of three

$s=\frac{3600s * 40h}{1h} = 144000s$

b) Using the line equation from the starting point (0 seconds, 1.5 V)

$m=\frac{1-1.5}{144000-0} = \frac{-0.5}{144000}$

where m denotes the slope.

$V-V_{1}=m(x-x_{1})$

where V represents voltage in volts and t signifies time in seconds

$V=m(t-t_{1}) + V_{1}$ along with P and m.

$V=-\frac{0.5}{144000} t + 1.5 V[tex] c) Using the equation VPOWER IS DEFINED AS:[tex] P(t) = v(t) * i(t) [tex]so.[tex] P(t) = 9mA * (-\frac{0.5}{144000} t + 1.5) [tex][tex]P(t) = - (31.25X10^{-9}) t + 0.0135$