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16 days ago

A 44-cm-diameter water tank is filled with 35 cm of water. A 3.0-mm-diameter spigot at the very bottom of the tank is opened and

water begins to flow out. The water falls into a 2.0-cm-diameter, 40-cm-tall glass cylinder. As the water falls and creates noise, resonance causes the column of air in the cylinder to produce a tone at the column's fundamental frequency. What are:
a. the frequency
b. the rate at which the frequency is changing (Hz/s) when the cylinder has been filling for 4.0 s? You can assume that the height of the water in the tank does not appreciably change in 4.0 s.

Physics

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You throw a tennis ball (mass 0.0570 kg) vertically upward. It leaves your hand moving at 15.0 m/s. Air resistance cannot be neg

Sav [3153]

The answer is 195 J.

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3 months ago

Why must the height of the meniscus in the graduated cylinder match the height of the water in the tub when measuring volume?

serg [3582]

Answer:

Refer to the explanation.

Explanation:

To grasp the concept, start with the fundamental idea of meniscus in a graduated cylinder.

"The meniscus refers to the curve noticed at the surface of a liquid due to its container. Depending on liquid surface tension and its adherence to the container’s walls, this meniscus may be concave or convex".

Given this definition, when measuring the volume of water, it's crucial to read the measurement at the bottom of the meniscus curve, as water forms a concave shape.

Taking the reading at eye level ensures an accurate volume, as it aligns with this method.

Additionally, this way of reading balances total pressure with atmospheric pressure by adjusting the cylinder's height to match the water level.

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3 months ago

A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it

Ostrovityanka [3204]

Response:D

Clarification:

Provided

mass of object $m=5 kg$

Distance traveled $h=10 m$

resulting velocity $v=12 m/s$

energy conservation occurs starting when the object begins its descent and reaches a speed of 12 m/s

Initial Energy $=mgh=5\times 9.8\times 10=490 J$

Final Energy $=\frac{1}{2}mv^2+W_{f}$

$=\frac{1}{2}\cdot 5\cdot 12^2+W_{f}$

where $W_{f}$ is the work done by friction, if any

$490=360+W_{f}$

$W_{f}=130 J$

As friction is present, this indicates an open system with a net external force of zero.

An open system allows for the exchange of energy and mass, and the presence of friction indicates that it is indeed an open system.

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3 months ago

A spaceship moves at a speed of 0.95 c away from the Earth. It shoots a star wars torpedo toward the Earthat a speed of 0.90 c r

Sav [3153]

Answer:

0.345 c

Explanation:

$v_{se}$ = speed of spaceship with respect to earth = 0.95 c

$v_{ts}$ = speed of torpedo with respect to spaceship = - 0.90 c

$v_{te}$ = speed of torpedo with respect to earth

The velocity of the torpedo in relation to earth is calculated as

$v_{te}=\frac{v_{se} + v_{ts}}{1 + \frac{v_{se}v_{ts}}{c^{2}}}$

$v_{te}=\frac{0.95c + (- 0.90 c)}{1 + \frac{(0.95 c)(- 0.90 c))}{c^{2}}}$

$v_{te}$ = 0.345 c

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2 months ago

A ball collides with a vertical, unmovable wall. There is no friction between the wall and the ball (the only force acting on th

Yuliya22 [3333]

Answer: in the same direction, meaning to the left.

Explanation:

The force acting perpendicularly to the surface in contact is such that it halts relative motion and, in the case of an elastic collision like this, restores the system's kinetic energy to its previous level. Thus, when a ball strikes an immovable surface, its speed (velocity magnitude) remains unchanged following the impact.

There will be a frictional force acting in parallel, but this should be examined separately for two main reasons:

The perpendicular force is constrained to the product of the coefficient of friction and the normal force. If this is insufficient to halt the ball, skidding will occur. The perpendicular force, which relies on the specific shape involved, does not align with the ball's center of mass, producing a torque that induces rotation. Once the ball rotates in such a way that the contact point is stationary, the momentum that would otherwise create friction force vanishes, causing the friction to cease, thus halting the ball's deceleration.

Consequently, the vertical component of the velocity will be inverted, whereas the horizontal component will be reduced to some extent, transferring a portion of kinetic energy into rotational energy. The rotation process will always negate the friction force before the horizontal velocity reaches zero, allowing the ball to keep moving in the same direction, albeit at a slower pace.

If instead you were to throw an elastic box (which wouldn't be able to rotate freely), it could indeed bounce back.

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2 months ago