Argon in the amount of 1.5 kg fills a 0.04-m3 piston cylinder device at 550 kPa. The piston is now moved by changing the weights

Since we can't see the image the teacher has provided, we must deduce its content based on clues from the answer choices. The image likely illustrates an atom containing 3 protons and 3 neutrons in the nucleus, along with 3 electrons orbiting it. If that is the case, Mike is correct (first choice) because the atomic number indicates the number of protons present in an atom. Since there are 3 protons, it corresponds to lithium, which has an atomic number of 3. The second choice is false, as electrons do not factor into atomic mass. The third and fourth options are also incorrect; regrettably, Joan does not grasp the concepts accurately.

Answer:

The total energy can be expressed as

Explanation:

The problem states that

The Poynting vector, which measures energy flux, equals

The rectangle's length is represented by

The width of the rectangle is

The duration considered is

Mathematically, the overall electromagnetic energy incident on the area is given by

where A denotes the area of the rectangle, calculated as

By plugging in the respective values

Again substituting values

The volumes are 200cm3 and 0.0002m3

Response: Numerous elements can be found, all situated within the same vertical column as bromine.

Explanation:

Elements are organized by their atomic numbers on the periodic table. Those in the same vertical column (known as groups) exhibit the same valence electron configurations, resulting in similar chemical characteristics. Consequently, there are numerous elements sharing analogous chemical properties grouped with Bromine.

Answer:

1/7 kg

Explanation:

Refer to the attached diagram for enhanced clarity regarding the question.

One of the blocks weighs 1.0 kg and accelerates downward at 3/4g.

g denotes the acceleration due to gravity.

Let M represent the block with known mass, while 'm' signifies the mass of the other block and 'a' refers to the acceleration of body M.

Given M = 1.0 kg and a = 3/4g.

By applying Newton's second law;

For the body with mass m;

T - mg = ma... (1)

For the body with mass M;

Mg - T = Ma... (2)

Combining equations 1 and 2 gives;

+Mg -mg = ma + Ma

Ma-Mg = -mg-ma

M(a-g) = -m(a+g)

Substituting M = 1.0 kg and a = 3/4g into this equation leads to;

3/4 g-g = -m(3/4 g+g)

3/4 g-g = -m(7/4 g)

-g/4 = -m(7/4 g)

1/4 = 7m/4

Multiplying gives: 28m = 4

m = 1/7 kg

Hence, the mass of the other box is 1/7 kg