Answer:
-13.18°C
Explanation:
To solve this issue, we must examine the principles associated with the rate of thermal conduction.
This rate is defined by the equation

Where,
Q = Amount of heat transferred
t = time
k = Thermal conductivity constant
A = Area of cross-section
Temperature difference across the material
d = Material thickness
The scenario indicates a heat loss that is double the initial value, which means

Substituting values yields,




Solving for
,

Thus, when the heat lost per second is doubled, the temperature on the external surface of the window is -13.18°C.
Let M denote the mass of the planet, n refer to the mass of the satellite, and r signify the radius of the planet. When the satellite is positioned at a distance r from the planet's surface, the separation between their centers is 2r. The gravitational force acting between them can be represented by the formula

, where G indicates the gravitational constant. If the satellite is positioned directly on the planet's surface, the distance between the two masses becomes r, and the gravitational force is represented as

. The answer is:

.
Answer:
The positioning of the object along the principal axis relative to the concave mirror.
Explanation:
In a concave mirror, the characteristics of the image generated depend on where the object is situated in relation to the mirror. The distance from the mirror to the object positioned along the principal axis is key.
The nearer the object is to the mirror, the larger or more magnified the image will appear. For example, placing an object between the focal point and the concave mirror's pole results in a significantly larger image compared to an object placed outside the center of curvature of the mirror.
Result:
1.60 g
Elucidation:
Based on the attached document:
we can infer that:

The distance covered in 2 seconds will be:
x = vt
x = 20 m/s × 2 s
x = 40 m
The segment corresponds to a quarter of a circle with radius r,
therefore, if 2 πr = 4 x
Then the radius (r) can be calculated as:

r = 25.5 m
Centripetal acceleration can be expressed as:

thus;

a = 15.7 m/s²
The acceleration magnitude suffered by your passengers in relation to the acceleration due to gravity can be calculated using:



∴ The acceleration magnitude experienced by your passengers while turning = 1.60 g