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LuckyWell
1 month ago
7

A transverse wave on a string has an amplitude A. A tiny spot on the string is colored red. As one cycle of the wave passes by,

what is the total distance traveled by the red spot?a.) 4Ab.) 1/2 Ac.) 1/4 Ad.) Ae.) 2A
Physics
1 answer:
Sav [3.1K]1 month ago
6 0
Since it's classified as a transverse wave, the particle on the string moves horizontally as the wave progresses, without actual forward or backward travel. Consequently, the red dot shifts 'A' to the left, returns 'A' to the center, moves 'A' to the right, and goes back 'A' to the center once again. Thus, the red dot collectively travels a distance totaling 4A.
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A parachutist, after opening her parachute, finds herself gently floating downward, no longer gaining speed. She feels the upwar
Sav [3153]

As the parachutist is descending at a steady rate

we can conclude that

a = \frac{dv}{dt}

Acceleration indicates the change in velocity

given the constant velocity in this scenario

a = 0

Thus, in this situation, we find the acceleration to be zero

It’s understood from Newton's second law

F_{net} = ma

where a is equal to 0

F_{net} = 0

F_{net} = F_g - F_b

Here, the force due to gravity

equals the force due to buoyancy

F_gHence, we can deduce

F_b

therefore

F_g - F_b = 0

as such the upward force is counteracted by the downward force.

5 0
1 month ago
So, why can a properly executed karate kick break a concrete block without fracturing bones [16]? first, bone is a very strong m
Yuliya22 [3333]
Contact me for the complete response, if it’s not too late.
3 0
1 month ago
the minute hand on a clock is 9 cm long and travels through an arc of 252 degrees every 42 minutes. To the nearest tenth of a ce
Ostrovityanka [3204]

Answer:

The distance covered by the minutes hand is 39.60 cm.

Explanation:

Note: A clock has a circular shape, where the minutes hand acts as the radius, and its motion creates an arc.

Length of an arc is calculated as ∅/360(2πr)

L = ∅/360(2πr).................... Equation 1π

Here, L represents the arc’s length, ∅ is the angle made by the arc, and r is the arc’s radius.

Given: ∅ = 252°, r = 9 cm, π = 3.143.

Upon substituting these values into equation 1,

L = 252/360(2×3.143×9)

L = 0.7×2×3.143×9

L = 39.60 cm.

Thus, the distance traversed by the minutes hand is 39.60 cm.

4 0
2 months ago
A camera operator is filming a nature explorer in the Rocky Mountains. The explorer needs to swim across a river to his campsite
inna [3103]

Answer:

a. Angle= 28.82°

b. Approved. Although he might feel cold, he should be able to cross.

Explanation:

Velocity Vector

Velocity is a measure of how quickly something is moving in a specific direction. It is represented as a vector that has both magnitude and direction. If an object can only move in one direction, then speed can serve as the scalar equivalent of that velocity (only focusing on magnitude).

a.

The explorer aims to swim across a river to reach his campsite, as depicted in the image below. The river's velocity is vr and the explorer's swimming speed in still water is ve. If he were to swim straight towards the campsite, he would end up downstream due to the river's current. Therefore, he must swim at an angle that allows him to overcome the current while still moving towards his goal. This angle relative to the shore is what we need to determine. The explorer's speed can be broken down into its horizontal (vx) and vertical (vy) components. In order to counteract the river's flow:

v_{ey}=v_r

We can calculate the vertical component of the explorer's swimming speed as

v_{ey}=|v_e|cos\alpha

Thus

v_r=|v_e|cos\alpha

Finding the value of \alpha

\displaystyle cos\alpha=\frac{v_r}{|v_e|}

\displaystyle cos\alpha=\frac{0.665}{0.759}=0.876

Then the angle is given by

\alpha=28.82^o

b.

The component of the explorer's velocity that goes horizontally is

v_{ex}=0.759sin28.82^o

v_{ex}=0.366\ m/s

This represents the actual velocity directed towards the campsite

Considering that

\displaystyle v=\frac{x}{t}

To find t

\displaystyle t=\frac{x}{v}

Calculating the duration for the explorer to cross the river

\displaystyle t=\frac{29.3}{0.366}

t=80\ sec

As this time is under the hypothermia threshold (300 seconds), the conclusion is

Approved. Although he will feel cold, he should manage to cross successfully.

3 0
2 months ago
Two radioactive nuclei A and B are present in equal numbers to begin with. Three days later, there are 4.04 times as many A nucl
inna [3103]
The half-life for substance A is determined to be 17.1 days. To explain: The half-life for substance B is noted to be 1.73 days. Let’s convert the 3 days elapsed time into terms of half-lives of B: 1.37 days equates to 1 half-life of B, implying 3 days translates to multiples of half-lives of B, specifically 2.19 half-lives. Consequently, the quantity of A in regard to B is expressed as follows: A = 4.04 B. For B, we can express the quantity after n half-lives as B0 / 2ⁿ. Hence, applying these relationships after 2.19 half-lives results in adjusting A similarly as A0 / 2ⁿ. Our derived equations lead us to relate the two expressions through substitutions where after cancelling A0, we derive the final calculation: 2ⁿ = 4.04 divided by 2^(2.19), which ultimately simplifies leading to 1 half-life of A totaling 17.1 days.
7 0
29 days ago
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