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dmitriy555
15 days ago
11

As the temperature of seawater increases from 15o C to 20o C, sound velocity through the seawater

Chemistry
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Put the following elements into five pairs of elements that have similar chemical reactivity: F, Sr, P, Ca, O, Br, Rb, Sb, Li, S
Anarel [2989]

Explanation:

Elements provided:

  F, Sr, P, Ca, O, Br, Rb, Sb, Li, S

Elements sharing similar reactivity belong to the same group in the periodic table, indicating that those in the same column exhibit comparable reactivity. Here are the identified groupings:

  Li and Rb are alkali metals in group 1

  Ca and Sr are alkaline earth metals in group 2

  F and Br are halogens in group 7

  O and S belong to group 6

 P and Sb are classified in group 5 of the periodic table

Thus, these classifications illustrate elements with the same chemical characteristics.

7 0
4 months ago
What is the density (in g/L) of a gas with a molar mass of 16.01 g/mol at 1.75 ATM and 337 K?
Anarel [2989]
To solve for density, you can use the formula--> Density= PM/ RT, where P stands for pressure, M for molar mass, R represents the gas constant, and T is temperature. 

P= 1.75 atm
M= 16.01 g/ mol
R= 0.0821 atm·L/ mol·K
T=337 k

Thus, the density calculation becomes: density= (1.75 x 16.01)/ (0.0821 x 337)= 1.01 g/L
8 0
2 months ago
Read 2 more answers
The value of delta G at 141.0 degrees celsius for the formation of phosphorous trichloride from its constituent elements,
VMariaS [2998]
The appropriate answer is option E. Gibbs free energy can be expressed using the equation: ΔG = ΔH - TΔS, where ΔH denotes the change in enthalpy of the reaction, T is the reaction temperature, and ΔS signifies entropy change. For our calculations, we have ΔH = -720.5 kJ/mol which converts to -720500 J/mol (given that 1 kJ = 1000 J), ΔS = -263.7 J/K, and T = 141.0°C, which equals 414.15 K. Consequently, the Gibbs free energy for the specified reaction at 141.0°C is calculated as -611.3 kJ/mol.
6 0
3 months ago
An electrochemical cell is constructed with a zinc metal anode in contact with a 0.052 M solution of zinc nitrate and a silver c
Tems11 [2777]
Q is determined to be 12.38. The Nernst equation is expressed as Ecell = E°cell - (2.303RT/nF) log Q, where Q represents the reaction quotient. The reaction quotient Q is calculated by taking the product of the products' concentrations divided by the product of the reactants' concentrations. For an electrochemical cell, Q is the concentration ratio of the solution at the anode compared to that at the cathode. Consequently, Q = [anode]/[cathode], specifically Q = 0.052/0.0042, arriving at a value of Q = 12.38.
6 0
3 months ago
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