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OlgaM077
2 months ago
10

The Rydberg constant is 3.3 x 10 15 Hz. this value is also

Chemistry
2 answers:
lorasvet [2.7K]2 months ago
7 0

Result:

The Rydberg constant of 3.3 x 10¹⁵ Hertz corresponds to 1.090 x 10⁷ m⁻¹

Justification:

Provided:

The Rydberg constant is 3.3 x 10¹⁵ Hz

1 Rydberg constant = 3.3 x 10¹⁵ Hz

1 Rydberg constant = 1.090 x 10⁷ m⁻¹

Thus, the Rydberg constant of 3.3 x 10¹⁵ Hertz translates to 1.090 x 10⁷ m⁻¹

alisha [2.9K]2 months ago
6 0

Result: The Ionization Frequency of Hydrogen

Justification: By utilizing the visible region and other types of light, distinct line spectra for excited states of a hydrogen atom were created. Rydberg formulated an empirical equation that describes the frequency separation between these lines:

ν =R [1/(n^2 l) −1/(n^2 u)]

with R being 3.3 x 10¹⁵ Hz. This equation is referred to as the Rydberg formula.

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1. For which of these elements would the first ionization energy of the atom be higher than that of the diatomic molecule?
alisha [2963]

Answer: The correct selection is (b).

Explanation:

The energy required to detach an electron from an atom or ion in its gaseous state is termed ionization energy.

This indicates that a smaller atom necessitates a greater amount of energy to remove its valence electron. The reason for this is that there exists a strong attraction between the nucleus and the electrons in smaller atoms or elements.

Therefore, a significant amount of energy is needed to dislodge the valence electrons.

The electronic configuration for helium is 1s^{2}. Hence, due to its fully occupied valence shell, it exhibits greater stability.

Consequently, a large amount of energy is needed to remove an electron from a helium atom.

In conclusion, from the choices provided, the ionization energy of helium will be greater than that of the diatomic molecule.

7 0
2 months ago
Marianne designs an experiment involving electrically charged objects. She wants to know which objects will be attracted to a ne
castortr0y [3046]

Answer:

The generation of static electricity occurs when two surfaces are rubbed together. This process causes a transfer of electrons, resulting in a build-up of negative charge. For instance, when you shuffle on a carpet, the friction creates multiple contact points which allow electrons to move onto you, thus accumulating a static charge. Touching another individual or object can lead to a sudden discharge, experienced as an electric shock.

In a similar way, rubbing a balloon against your hair generates opposite static charges on both your hair and the balloon. As you gently pull the balloon away from your head, the attraction between these opposite charges can be observed, causing your hair to rise.

Materials

• Balloon

• Woolen item (like a sweater, scarf, or yarn ball)

• Stopwatch

• Wall

• Partner (optional)

Preparation

• Inflate the balloon and secure the end.

• Have your partner ready to time with the stopwatch.

Procedure

• Grip the balloon with minimal hand coverage, such as holding it with just your thumb and index finger, or by its tied neck.

• Rub the balloon on the wool item once, making sure to go in one direction only.

• Press the rubbed side of the balloon against the wall and let go. Is it adhering to the wall? If it's stuck, your partner should start the stopwatch to measure how long it stays there. If it doesn’t stick, continue to the next step.

• Briefly touch the balloon to a metal object. Why is this step necessary?

• Repeat this procedure, but each time increase the number of rubs against the woolly item, ensuring the direction remains the same (do not rub back and forth).

Observations and results

As you increase the number of times you rub the balloon on the woolly material, does the duration of its adhesion to the wall increase?

Wool is an excellent conductor; it easily relinquishes electrons. When you rub wool on a balloon, electrons move from the wool to the surface of the balloon, imparting a negative charge to the rubbed area. Balloons, made from rubber, act as insulators, which means not all areas of the balloon will have a negative charge—only where it was rubbed will have a negative charge, while the rest of the balloon remains neutral.

Once the balloon is sufficiently charged negatively by repeated rubbing, it will adhere to the wall. Though the wall typically has a neutral charge, its internal charges can realign such that a positively charged region can attract the negatively charged balloon. Since the wall is also an insulator, the charge does not dissipate instantly. However, when the balloon is in contact with a metal object, the excess electrons from the balloon flow into the metal quickly, making the balloon lose its attraction and peel away.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST

6 0
2 months ago
Read 2 more answers
Bonds between two atoms that are equally electronegative are _____. bonds between two atoms that are equally electronegative are
Alekssandra [3086]
When two atoms with equal electronegativity bond together, they form nonpolar covalent bonds.

Your second statement mirrors the first; the second statement likely reads, "Bonds between two atoms with unequal electronegativity are termed polar covalent bonds."
4 0
3 months ago
A particular car has a gas mileage of 24.5 miles per gallon. If the cost of gas is $4.25 per gallon, and the car travels at a co
KiRa [2933]

Response:

$30.39

Rationale:

a lot of calculations

3 0
1 month ago
Write the formulas for the following ionic compounds: (a) copper bromide (containing the Cu+ ion), (b) manganese oxide (containi
Anarel [2989]

Answer: The formulas for the ionic compounds are:

a)CuBr

b)Mn_2O_3

c)Hg_2I_2

d)Mg_3(PO_4)_2

Explanation:

Determining the formulas for ionic compounds relies on:

The criss-cross method, wherein the oxidation states of ions are exchanged, forming the subscripts of the respective ions, resulting in a neutral compound.

(a) Copper bromide is formed based on the Cu^+ ion.

Cu^++Br^-\rightarrow CuBr

(b) Manganese oxide originates from the inclusion of the Mn^{3+} ion.

Mn^{3+}+O^{2-}\rightarrow Mn_2O_3

(c)Mercury iodide contains the Hg_2^{2+}

Hg_2^{2+}+I^-\rightarrow Hg_2I_2

(d) Magnesium phosphate includes the PO_4^{3-}

Mg^{2+}+PO_4^{3-}\rightarrow Mg_3(PO_4)_2

4 0
2 months ago
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