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nekit
18 days ago
8

Explain how collecting mean values (X-bar) from samples drawn from a dataset, regardless of the statistical distribution of the

dataset, results in a distribution of those values that is centered on the mean value of the original dataset and is approximately normally distributed depending upon the sample size used. Include the name the theorem that describes this phenomenon, and discuss what it means to treat the X-bar data points derived from sampling as a new random variable. Why is this important in engineering?
Engineering
1 answer:
Kisachek [356]18 days ago
8 0

Answer:

The response is presented below

Explanation:

Central Limit Theorem: The CLT is a statistical principle asserting that if a sample size is sufficiently large and shows minimal variation from the population, the average of all samples will approximate the mean of that population. Furthermore, all distributions can be modeled as nearly normal.

This principle is illustrated by the central limit theorem. Specifically, if we gather independent random samples of size n from any kind of population, a large n will yield a sample distribution that aligns with a normal distribution pattern.

mean of the sample means

                    \mu _\bar x = \mu.............1

while the standard deviation of the sample means is

                      \mu _\bar x = \frac{\sigma }{\sqrt{n}}.........2

and This theory has findings applicable elsewhere in statistical studies. Although it may initially seem theoretical and lacking real-world utility, the Central Limit Theorem is crucial for applying statistics effectively in practice.

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1. Mark ‘N’ if a wrong type of units is used. Mark ‘Y’ otherwise. (1 point each)
pantera1 [306]

Response:

bsbsdbsd

Clarification:

7 0
1 month ago
A 227 pound compressor is supported by four legs that contact the floor of a machine shop. At the bottom of each leg there is a
choli [298]

Answer:

1.312 in

Explanation:

The details provided in the question are:

The weight of the compressor, W is 227 pounds.

It has 4 legs.

The maximum permissible pressure is 42 psi.

Let F represent the force exerted by each leg.

Thus,

W = 4F,

or

227 pounds = 4F,

implying that:

F = 56.75 pounds.

Furthermore,

Force = Pressure × Area,

therefore:

56.75 pounds = 42 psi × πr²  [ r signifies the radius of one leg]

Consequently, we find:

r² = 0.4301,

and thus:

r = 0.656;

resulting in a diameter equal to 2r = 2 × 0.656,

which equals 1.312 in.

6 0
1 month ago
Six years ago, an 80-kW diesel electric set cost $160,000. The cost index for this class of equipment six years ago was 187 and
grin007 [323]

Answer:

total expense for the new boiler = $229706.825

total expense for new boiler = $127512

Explanation:

provided information

initial power p1 = 80 kW

price C = $160000

cost index CI 1 = 187

cost index CI 2= 194

capacity factor f = 0.6

subsequent power p2 = 120 kW

present cost = $18000

to determine

total expense and cost for 40 kW

solution

we evaluate CN cost for the new boiler and CO cost for the existing boiler

where x represents the capacity of the new boiler

first we compute the current cost of the old boiler which is

current cost CO = C × \frac{CI 1 }{CI 2 }.............1

substituting the value here

current cost = 160000 × \frac{194 }{187 }

updated current cost = $165989.304

and

employing power sizing strategy for 124 kW

CN/CO = (\frac{p2}{p1} )^{f}...............2

insert value and calculate CN

CN/CO = (\frac{p2}{p1} )^{f}  

CN / 165989.304 = (\frac{120}{80} )^{0.6}  

CN = 211706.825

therefore the new expense = $211706.825

hence

total expense for the new boiler amounts to

total expense = new expense + current cost

total exp = 211706.825 + 18000

boiler expense total = $229706.825

and

concerning a 40 kW unit, the calculated new cost will be

applying equation 2

CN/CO = (\frac{p2}{p1} )^{f}

CN / 165989.304 = (\frac{40}{80} )^{0.6}  

CN = 109512

thus the new cost is $109512

therefore

total expense for the new boiler is

total exp = new cost + current cost

total expense = 109512 + 18000

total cost for the new boiler = $127512

7 0
1 month ago
2.31 LAB: Simple statistics Part 1 Given 4 integers, output their product and their average, using integer arithmetic. Ex: If th
iogann1982 [368]

Answer:

Explanation:

Un dato importante: la división entera elimina la parte fraccionaria. Por lo tanto, el promedio de 8, 10, 5 y 4 se presenta como 6, no 6.75.

Observación: Las pruebas incluyen cuatro valores de entrada muy grandes cuyo producto causa desbordamiento. No necesitas hacer nada especial, solo ten en cuenta que la salida no representa el producto correcto (en realidad, el resultado de cuatro números positivos es negativo; sorprendente).

Envía lo anterior para evaluación. Tu programa no pasará las últimas pruebas (eso es normal) hasta que completes la segunda parte a continuación.

Parte 2: Además, se debe calcular e imprimir el producto y promedio usando aritmética de punto flotante.

Presenta cada número de punto flotante con tres dígitos después del punto decimal, lo cual puedes hacer así: System.out.printf("%.3f", tuValor);

Ejemplo: Si la entrada es 8, 10, 5, 4, la salida sería:

import java.util.Scanner;

public class LabProgram {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

int num3;

int num4;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

num3 = scnr.nextInt();

num4 = scnr.nextInt();

double average_arith = (num1 + num2 + num3 + num4) / 4.0;

double product_arith = num1 * num2 * num3 * num4;

int result1 = (int) average_arith;

int result2 = (int) product_arith;

System.out.printf("%d %d\n", result2, result1);

System.out.printf("%.3f %.3f\n", product_arith, average_arith);

}

}

Expected output: 1600.000 6.750

5 0
1 month ago
Read 2 more answers
Madison and Oxford are the same distance from the equator and they are both near the ocean. Use the information on the map to an
pantera1 [306]

Answer:

The air temperature should be similar in both regions.

Explanation:

Climate conditions differ globally. Additionally, factors such as distance from the ocean, landscape, and elevation influence these conditions.

If both areas are equidistant from the equator and close to the ocean, there is a high likelihood that they will have similar climate conditions, thus resulting in comparable temperature ranges.

4 0
13 days ago
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