John runs 500 feet in 1 minute. Identify the correct conversion factor setup required to compute John's speed in inches per seco

Question

Snowcat

8 days ago

15

John runs 500 feet in 1 minute. Identify the correct conversion factor setup required to compute John's speed in inches per seco

nd.

Mathematics

2 answers:

PIT_PIT [3.9K] · Answer 1 · 2026-02-25T05:58:00+03:00

PIT_PIT [3.9K]8 days ago

7 0

Answer:

refer to the method

Step-by-step explanation:

Keep in mind that

$1\ ft=12\ in$

To change feet to inches, multiply by 12

$1\ min=60\ sec$

To convert minutes into seconds, multiply by 60

we have

$500\frac{ft}{min}=500(\frac{12}{60})=500(\frac{1}{5})=100\frac{in}{sec}$

Inessa [3.9K] · Answer 2 · 2026-02-25T05:57:58+03:00

Answer:

$\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}$

Step-by-step explanation:

We know John runs 500 feet within 1 minute. We need to identify the correct setup of conversion factors needed to calculate John's speed in inches per second.

It is established that 1 minute equals 60 seconds and 1 foot is equivalent to 12 inches.

$\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}$

Thus, our necessary conversion factor setup would be $\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}$ .

Now, let's convert 500 feet in 1 minute into inches per second:

$\frac{500}{1}\times \frac{1}{\text{ 60 sec}}\times \frac{12\text{ inches}}{1}$

$\frac{500}{1}\times \frac{1}{\text{ 5 sec}}\times \frac{1\text{ inches}}{1}$

$\frac{500\text{ inches}}{\text{ 5 sec}}$

$\frac{100\text{ inches}}{\text{ sec}}$

Thus, John runs at a speed of 100 inches per second.