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Snowcat
1 month ago
15

John runs 500 feet in 1 minute. Identify the correct conversion factor setup required to compute John's speed in inches per seco

nd.
Mathematics
2 answers:
PIT_PIT [12.4K]1 month ago
7 0

Answer:

refer to the method

Step-by-step explanation:

Keep in mind that

1\ ft=12\ in

To change feet to inches, multiply by 12

1\ min=60\ sec

To convert minutes into seconds, multiply by 60

we have

500\frac{ft}{min}=500(\frac{12}{60})=500(\frac{1}{5})=100\frac{in}{sec}

Inessa [12.5K]1 month ago
5 0

Answer:

\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}

Step-by-step explanation:

We know John runs 500 feet within 1 minute. We need to identify the correct setup of conversion factors needed to calculate John's speed in inches per second.

It is established that 1 minute equals 60 seconds and 1 foot is equivalent to 12 inches.

\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}

Thus, our necessary conversion factor setup would be \frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}.

Now, let's convert 500 feet in 1 minute into inches per second:

\frac{500}{1}\times \frac{1}{\text{ 60 sec}}\times \frac{12\text{ inches}}{1}

\frac{500}{1}\times \frac{1}{\text{ 5 sec}}\times \frac{1\text{ inches}}{1}

\frac{500\text{ inches}}{\text{ 5 sec}}

\frac{100\text{ inches}}{\text{ sec}}

Thus, John runs at a speed of 100 inches per second.

   

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