The strength of the electric field is determined by Solution: As the question states, the area of the electrode is given, and the charge, q, equals 50 nC. To compute the electric field strength, we need to first ascertain the surface charge density which is defined as... Thus, the electric field strength above the center of the electrode can be calculated as:
Arginine is classified as a basic amino acid since it has two amino groups alongside a single acid group.
At a low pH level, all ionizable groups are protonated. As the pH rises slightly, the acid group loses its proton. When the pH increases further, one of the amino groups also loses a proton. At considerably high pH levels, none of the ionizable groups remain protonated.
Pkas
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<span>
pka1 = 1.82
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<span>
pka2 = 8.99
</span>
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pka3 = 12.48
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</span>
</span></span>
Thus, 9.20 is above the second pKa and below the third pKa. This indicates that the acid has already lost its proton, as has one of the amino groups, while the second amino group remains protonated. When an acid is not protonated, it carries a negative charge. An unprotonated amino group is neutral, whereas when protonated, the amino group bears a positive charge. Therefore, this amino acid exhibits one positive charge (from one of the amino groups) and one negative charge (from the acid), resulting in an overall neutral charge.
