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AleksandrR
1 month ago
14

A rock is launched vertically upward by a slingshot. The elastic band of the slingshot accelerates the rock from rest to 40 m/s

in a distance of 10 cm. How long will the rock take to return to its release point (time of flight)? Neglect air resistance.
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
5 0

Answer:

0.016 s

Explanation:

Starting speed, u = 0

Utilize the third equation of motion to calculate the acceleration of the rock.

2as=v^2-u^2\\a = \frac{40^2-0}{2\times0.1} =8000 m/s^2

The overall displacement in the vertical axis will be zero. y = 0

Apply the second equation:

s=ut+\frac{1}{2}at^2\\0=0+\frac{1}{2}(8000)t^2\\t= 0.016 s

Therefore, the rock will come back to its original launch position in 0.016 s.

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Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and
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3 0
1 month ago
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The formula for the kinetic energy of any object in motion is

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For the object you've mentioned, it translates to

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