To tackle this question, we know the following:
1 Albert equals 88 meters.
1 A = 88 m.
Initially, we square both sides of the equation:
(1 A)^2 = (88 m)^2
1 A^2 = 7,744 m^2
<span>Since 1 acre equals 4,050 m^2, let’s divide both sides by 7,744 to find out how many acres match this value:</span>
1 A^2 / 7,744 = 7,744 m^2 / 7,744
(1 / 7,744) A^2 = 1 m^2
Then multiply both sides by 4,050.
(4050 / 7744) A^2 = 4050 m^2
0.523 A^2 = 4050 m^2
<span>Thus, one acre is approximately 0.52 square alberts.</span>
Answer:
The direction in which a vehicle accelerates aligns with its velocity direction. However, the force of acceleration works against the car's speed.
Explanation:
The car’s initial acceleration can be found using:
v = v₀ + a t
a = (v-v₀) t
which assumes the initial speed is zero (v₀ = 0 m/s).
a = v / t
a = 300 / t
The acceleration vector matches the direction of the vehicle's movement.
Upon hitting the wall, a force is exerted in the reverse direction to halt the car, thus this acceleration opposes the vehicle’s speed. However, the module should be much greater since the stopping distance is minimal.
Answer:
A = 4.76 x 10⁻⁴ m²
Explanation:
Given data:
Person's weight = 625 N
Bike's weight = 98 N
Pressure per tire = 7.60 x 10⁵ Pa
Find: Contact area per tire
Total system weight = 625 + 98 = 723 N
Let F represent the force supported by each tire
2F = 723 N
Therefore, F = 361.5 N
Using the formula F = P × A
Contact area, A = 4.76 x 10⁻⁴ m²
Answer:
The primary factors that influence the intensity of shaking during an earthquake include the depth of the quake, its distance from the fault line, the type of soil below, and specifics about the buildings—especially their height. We will focus on the last two (soil quality and structures) and their interaction.
Answer:
Explanation:
Density is defined as d=m/v.
To find mass, the formula transforms into:
m=d*v
m=2700*54.3
m=146610
m=14.6*10^4
