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salantis
1 month ago
15

If the earth was a guava fruit, the space where the seeds are would be the core/mantle​

Chemistry
2 answers:
Anarel [2.9K]1 month ago
8 0
Nice examination haha...
lorasvet [2.7K]1 month ago
4 0
Exactly! I have to respond to a question before mine gets addressed, so here I am:)
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Assuming that only the listed gases are present, what would be the mole fraction of oxygen gas be for each of the following situ
eduard [2782]

Mole fraction of oxygen gas: 0.381

Additional clarification

Given:

2.31 atm Oxygen

3.75 atm Hydrogen

Required:

Mole fraction of Oxygen

Calculation:

According to Dalton’s Law of partial pressures

P tot = P₁ + P₂ +.. + Pₙ

Substituting values:

P tot = P O₂ + P H₂

P tot = 2.31 atm + 3.75 atm

P tot = 6.06 atm

Mole fraction of O₂ (X O₂):

P O₂ = X O₂ x P tot

X O₂ = P O₂ / P tot

X O₂ = 2.31 / 6.06

X O₂ = 0.381

6 0
1 month ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Ca2+, V5+, Br-
lorasvet [2795]

Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

  • The ionic compound must exhibit neutrality; its total charge should equal zero.
  • A binary ionic compound is formed from two distinct ions.

Ca²⁺ combines with either Br⁻ or S²⁻ to create binary ionic compounds.

  • CaS is created when Ca²⁺ pairs with S²⁻ resulting in the neutral binary ionic compound CaS.
  • CaBr₂ results from the combination of one mole of Ca²⁺ with two moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

V⁵⁺ can also unite with either Br⁻ or S²⁻ to produce binary ionic compounds.

  • V₂S₅ is formed when two moles of V⁵⁺ bond with five moles of S²⁻ yielding the neutral binary ionic compound V₂S₅.
  • VBr₅ is produced by combining one mole of V⁵⁺ with five moles of Br⁻ to form the neutral binary ionic compound VBr₅.

Thus, the empirical formulas for four binary ionic compounds that may be produced are: CaS, CaBr₂, VBr₅, and V₂S₅.

5 0
1 month ago
How would a flood be a limitation for synthetic polymers that rely on natural rubber in its production?
eduard [2782]
A flood that affects the environment where natural rubber is produced would severely hinder rubber production. In order to greatly limit production, a flood would need to destroy a significant portion of rubber trees. Natural rubber is crucial for manufacturing synthetic polymers. If the rubber supply is compromised (due to the disruption of its ecosystem caused by a flood), there would be a substantial decline in the availability of synthetic polymers.


hope this helps
3 0
1 month ago
Read 2 more answers
What is the molar mass of citric acid (C6H8O7) and baking soda (NaHCO3)?
Alekssandra [3086]

Answer:

1. 192.0 g/mol.

2. 84.0 g/mol.

Explanation:

  • The molar mass refers to the weight of all atoms combined in a molecule measured in grams per mole.
  • To find a molecule's molar mass, we begin by looking up the atomic weights of the relevant elements from the periodic table. Next, we tally the atoms present and multiply that by their respective atomic weights.

1. Molar mass of citric acid (C₆H₈O₇):

Molar mass of C₆H₈O₇ = 6(atomic mass of C) + 8(atomic mass of H) + 7(atomic mass of O) = 6(12.0 g/mol) + 8(1.0 g/mol) + 7(16.0 g/mol) = 192.0 g/mol.

2. Molar mass of baking soda (NaHCO₃):

Molar mass of NaHCO₃ = (atomic mass of Na) + (atomic mass of H) + (atomic mass of C) + 3(atomic mass of O) = (23.0 g/mol) + (1.0 g/mol) + (12.0 g/mol) + 3(16.0 g/mol) = 84.0 g/mol.

4 0
1 month ago
what is the net ionic equation with its physical states? (NH4)2CO3(aq)+Ca(ClO4)2(aq)⟶CaCO3(s)+2NH4ClO4(aq)
lions [2927]

Answer: The net ionic equation is CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

Explanation:

A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.

(NH_4)_2CO_3(aq)+Ca(ClO_4)_2(aq)\rightarrow CaCO_3(s)+2NH_4ClO_4(aq)

The ion-based representation of the equation is:

2NH_4^+(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2ClO_4^{-}(aq)\rightarrow CaCO_3(s)+2NH_4^{+}(aq)+2ClO_4^-(aq)

"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.

Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.

Therefore, the net ionic equation is:

CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

6 0
1 month ago
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