Answer:
11.56066 m/s
Explanation:
m = Mass of individual
v = Velocity of individual = 13.4 m/s
g = Gravitational acceleration = 9.81 m/s²
v' = Velocity of the individual after dropping
At the surface, kinetic and potential energy will equalize

The cliff's height is 9.15188 m
Define fall height as h' = 2.34 m

The person's speed is 11.56066 m/s
Boris's reaction time is denoted as t(r), implying that he has not jumped prior to that moment. Therefore, H(b)(t) equals 0
. The vertical displacement is determined simply as
D(t) = H(a)(t)
(B) (length)/(time³) Explanation: The term x = ½ at² + bt³ should meet dimensional consistency. This means that both bt³ and ½ at² must share the same units, which are length. To find the dimension of b, we rearrange the equation: [x] = [b]*[t]³ leads to length = [b]*time³, hence [b] = length/time³.
Answer:
a) 
b) 
c) 
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.


(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.


Utilizing
in our first equation (1)


Now let’s solve for t.

The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.

b) To determine the velocity magnitude just before impact, we must calculate both x and y components.


The computed velocity magnitude is:

c) The ball's angle is:
