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Alona
7 days ago
5

Another path in the community is 2.1 miles long. It has benches at 1/3 And 2/3 of the distance from beginning to end of the path

. How far in miles (5280=one mile ) is each bench from the beginning of the path?
Mathematics
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PQ⊥PS , m∠QPR=7x−9, m∠RPS=4x+22<br> Find : m∠QPR
zzz [12365]

Given:

It is stated that

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the measure of ∠QPR.

Formula

According to the problem PR sits between PQ and PS,

Consequently,

∠QPR+∠RPS = 90°

Now,

Inserting the values for ∠RPS and ∠QPR yields

7x-9+4x+22 = 90

or, 11x = 90-22+9

or, 11x = 77

or, x = \frac{77}{11}

or, x = 7

Substituting the value of x = 7 into ∠QPR gives us

∠QPR = 7(7)-9

or, ∠QPR = 40^\circ

So,

The measure of ∠QPR is 40°.

3 0
3 months ago
Alonso went to the market with \$55$55dollar sign, 55 to buy eggs and sugar. He knows he needs a package of 121212 eggs that cos
PIT_PIT [12445]

Answer: See explanation

Step-by-step explanation:

To determine how many boxes of sugar Alonso can purchase, we can express the scenario as follows:

= 2.75 + 11.50S ≤ 55

Expanding this gives us:

2.75 + 11.50S ≤ 55

11.50S ≤ 55 - 2.75

11.50S ≤ 52.25

S ≤ 52.25 / 11.50

S ≤ 4.54

Thus, he is able to buy 4 boxes of sugar.

3 0
3 months ago
Vicky did a survey to answer the following question: What is the average fitness score of grade 8 students? The mean fitness sco
PIT_PIT [12445]
The mean is found by summing all data values and dividing that total by the number of values.

The mean fitness score equals 3.2 points. If every student had the identical score, each student's fitness score would be 3.2 points.

Therefore, the correct choice is D. 3.2 points.
3 0
2 months ago
Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number
tester [12383]

Answer:Part a) 2,50,18

Part b) When Jenny divides the square root of her favorite positive integer by \sqrt{2}, the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For x=2

\sqrt{2}*\sqrt{2}=\sqrt{4}=2 -----> the product results in an integer

thus

The number x=2could potentially be Jenny's favorite positive integer

2) For x=50

\sqrt{50}*\sqrt{2}=\sqrt{100}=10 -----> the product results in an integer

thus

The number x=50could potentially be Jenny's favorite positive integer

3) For x=18

\sqrt{18}*\sqrt{2}=\sqrt{36}=6 -----> the product results in an integer

thus

The number x=18could potentially be Jenny's favorite positive integer

Part B)

1) For x=2

\sqrt{2}/\sqrt{2}=\sqrt{1}=1 -----> the outcome is an integer

2) For x=50

\sqrt{50}/\sqrt{2}=\sqrt{25}=5 -----> the outcome is an integer

3) For x=18

\sqrt{18}/\sqrt{2}=\sqrt{9}=3 -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by \sqrt{2}, she obtains an integer as a result.

4 0
2 months ago
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