Two pots are identical except that the flat bottom of one is aluminum, whereas that of the other is copper. Water in these pots
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Answer
Data provided:
mass of the block = 200 g = 0.2 Kg
Velocity at A = 0 m/s
Velocity at B = 8 m/s
distance of slide = 10 m
height of the block = 4 m
calculation for the block's potential energy
P = m g h
P = 0.2 x 9.8 x 4
P = 7.84 J
kinetic energy calculated as
Work done = P - KE
work = 7.84 - 6.14
work = 1.7 J
b) using the formula v² = u² + 2 a s
0 = 8² - 2 x a x 10
a = 3.2 m/s²
ma - μ mg = 0
Since you've completed parts a and b, I will tackle part c.
For part C
To respond to this question, we must identify the zeros of the velocity function:
This polynomial can be factored:
Finding the zeros now becomes straightforward since the function equals zero when any factor is zero.
By solving these equations, we identify our zeros:
The particle remains stationary at t=0 and t=3/2.
For part D
We must discover when the velocity function exceeds zero. We will utilize its factored form.
We will assess when each factor is greater than zero and compile the findings in the following table:
From the table, it's evident that our function is positive when
and t>3/2.
This indicates the interval during which the particle moves forward.
For part E
The distance traveled can be represented as:
We simply substitute t=12 to calculate the total distance traveled:
For part F
Acceleration is defined as the rate at which velocity changes.
We determine acceleration by deriving the velocity function concerning time.
To find the acceleration at 1 second, we substitute t=1s into the previous equation:
For part C
To respond to this question, we must identify the zeros of the velocity function:
This polynomial can be factored:
Finding the zeros now becomes straightforward since the function equals zero when any factor is zero.
By solving these equations, we identify our zeros:
The particle remains stationary at t=0 and t=3/2.
For part D
We must discover when the velocity function exceeds zero. We will utilize its factored form.
We will assess when each factor is greater than zero and compile the findings in the following table:
From the table, it's evident that our function is positive when
This indicates the interval during which the particle moves forward.
For part E
The distance traveled can be represented as:
We simply substitute t=12 to calculate the total distance traveled:
For part F
Acceleration is defined as the rate at which velocity changes.
We determine acceleration by deriving the velocity function concerning time.
To find the acceleration at 1 second, we substitute t=1s into the previous equation: