Response:
0.60 m/s
Details:
The average speed between times t = a and t = b can be expressed as:
v_avg = (x(b) − x(a)) / (b − a)
Given the function x(t) = 0.36t² − 1.20t, and considering the interval from 1.0 to 4.0:
v_avg = (x(4.0) − x(1.0)) / (4.0 − 1.0)
v_avg = [(0.36(4.0)² − 1.20(4.0)) − (0.36(1.0)² − 1.20(1.0))] / 3.0
v_avg = [(5.76 − 4.8) − (0.36 − 1.20)] / 3.0
v_avg = [0.96 − (-0.84)] / 3.0
v_avg = 0.60
The average speed calculated is 0.60 m/s.
Based on my findings, within a period of 2 hours, there are certain atoms remaining.
N = N0 * 2^(-t/6.020) = N = N0 * 2^-0.33223 = 0.7943 N0
Thus, the quantity of atoms that undergo disintegration is N0 - N = N0 * (1 - 0.79430) = 0.2057 N0
This must equate to 15 mCi = 15 * 3.7 * 10^7 = 5.55 * 10^8 atoms
N0 = 5.55 * 10^8 / 0.2057 = 2.698 * 10^9 atoms
Consequently, 2.698 * 10^9 atoms represents the value of N0.
Answer:
The pressure measured at this moment is 0.875 mPa
Explanation:
Given that,
Flow energy = 124 L/min
Boundary to system P= 108.5 kJ/min
We are tasked with finding the pressure here
Applying the pressure formula
Here, 
Where, v refers to velocity
Insert the values into the equation
Therefore, the pressure at this moment is 0.875 mPa
20.7 volts. The mass of an electron is 9.1 x 10⁻³¹ kg, and its wavelength is 0.27 x 10⁻⁹ m. The velocity of the electron can be determined using de Broglie's equation λ mv = h. Substituting the known values, we arrive at v = 2.7 x 10⁶ m/s. The potential difference through which the electron accelerates is noted, with the charge on an electron being 1.6 x 10⁻¹⁹ C. According to the conservation of energy, (0.5) mv² = q ΔV leads to ΔV = 20.7 volts.
