Answer:
The air exiting from the hairdryer is moving at a speed of 10 m/s.
Explanation:
The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram

by substituting
,
into the equation and resolving for
we find:



This thrust is linked to the speed of air ejection
through the equation

where
signifies the rate of air ejection, which is known to be

and since
,


by inserting these values into equation (2), we obtain the value of
as:

resulting in


which indicates the air velocity discharged from the hairdryer.
Answer:

Explanation:
Consider the following:
Length= 2L
Linear charge density=λ
Distance= d
K=1/(4πε)
The electric field measured at point P



Thus,

Now, by applying integration to the equation above

The string does not experience any force of tension, as it balances two forces acting in the same direction. Hence, the tension is zero.
Explanation:
If tension existed in the string, it would mean that two equal but opposite forces are exerting pull in contrary directions.
When a force of f newtons is applied from the right and another force of f newtons from the left, the resulting action occurs through one force. Because there is action on the same string in opposing directions, the tension in the string can only be equal to the magnitude of the string itself.
Therefore, the string indeed has no tension since it is dealing with two forces acting in the same direction. Thus, the tension is zero.
The force is calculated by multiplying mass and gravitational acceleration (F= mg). To find the solution, the mass of the elephant (5600 kg) is multiplied by gravity (9.8 m/s²). The result is 55,880 N, representing the upward gravitational force the elephant exerts on the Earth.
Answer:

Explanation:
Given,
Voltage of the primary coil (V_p) = 30 kV-rms
Voltage of the secondary coils (V_s) = 345 kV-rms
number of turns in the primary coil (n_p) = 80 turns
number of turns in the secondary coil (n_s) =?
the ratio of turns between primary and secondary coils






The number of turns in the secondary coil is equal to 