d a and b: it vibrates in both scenarios but differs in whether the sound is audible or not. The absence or presence of molecules does not prevent the tuning fork from vibrating, but it can obstruct hearing, as sound necessitates a mechanical wave medium. This brings us to (c) where the vibrations do occur, but they cannot reach your ears due to the lack of a medium.
vf^2 = 2ad
vf^2 = 2(9.81)(44m)
vf^2 = 863.28
vf = √863.28
vf = 29.4 - using equations of motion
ME = PE + KE
ME = mgh + 1/2mv^2
ME = (1)(9.81)(44) + 1/2(1)(3^2)
ME = 431.64 + 4.5
ME = 436.14 - applying the principle of energy conservation
hope this helps:)
Answer:
44.4m/s^2
Explanation:
Utilize the equation...S = ut + 1/2at^2
where...S = 32m...u = 0m/s....t = 1.20s
32 = (0)(1.20) + 0.5(1.20^2)a
; The acceleration due to gravity is 44.4m/s^2
Δd = 23 cm. When the eta string of the guitar has nodes at both ends, the resulting waves create a standing wave, which can be expressed with the following formulas: Fundamental: L = ½ λ, 1st harmonic: L = 2 ( λ / 2), 2nd harmonic: L = 3 ( λ / 2), Harmonic n: L = n λ / 2, where n is an integer. The rope's speed can be calculated using the formula v = λ f. This speed remains constant based on the tension and linear density of the rope. Now, let's determine the speed with the provided data: v = 0.69 × 196, yielding v = 135.24 m/s. Next, we will find the wavelengths for the two frequencies: λ₁ = v / f₁, which gives λ₁ = 135.24 / 233.08, equaling λ₁ = 0.58022 m; λ₂ = v / f₂ results in λ₂ = 135.24 / 246.94, consequently λ₂ = 0.54766 m. We'll substitute into the resonance equation Lₙ = n λ/2. At the third fret, m = 3, therefore L₃ = 3 × 0.58022 / 2, resulting in L₃ = 0.87033 m. For the fourth fret, m = 4, which gives L₄ = 4 × 0.54766 / 2, equating to L₄ = 1.09532 m. The distance between the two frets is Δd = L₄ – L₃, so Δd = 1.09532 - 0.87033, leading to Δd = 0.22499 m or 22.5 cm, rounded to 23 cm.
Answer:
v = 66.4 m/s
Explanation:
We know that the aircraft starts off moving at a speed of
now we have
in the Y direction, we can apply kinematic equations
as there is no acceleration along the x-axis, the velocity in this direction remains unchanged
thus yielding
