Balance the following reaction. A coefficient of \"1\" is understood. Choose option \"blank\" for the correct answer if the coef

Answer:

• Please refer to the attached image for the graph with labeled axes and points.

Explanation:

This is a guide to fulfilling the instructions along with essential notes for understanding how to create such graphs:

1) The horizontal axis should indicate pressure ranging from 0 mb to 760 mb, while the vertical axis corresponds to volume ranging from 0 to 1 mL.

The x-axis captures the independent variable, and the y-axis records the dependent variable. Both axes must be accurately labeled, showing the variable names and their respective units.

In this context, the origin, (0,0), signifies the intersection of the axes at a pressure of 0 mb and a volume of 0.0 milliliters.

2) Allocate values for the divisions on the axes to maximize the usage of space on both.

An effective graph aims to utilize the entire space on both axes; for this, identify the maximum values for pressure and volume, and determine the corresponding marks.

The pressure range along the x-axis is [90, 760 mb], suggesting large divisions of 100 mb, with the farthest right mark at 800 mb. You can then subdivide each 100 mb interval into 10 smaller sections, using small divisions of 10 mb (my example employs 4 sections of 25 mb, but 10 mb is preferable).

The volume's range for the vertical axis is [0.1, 0.8], so it’s best to use divisions set at 0.1 ml.

3) Next, identify and label the points as follows:

• (90, 0.9) ⇒ 90 mb, 0.9 ml

• (100, 0.8) ⇒ 100 mb, 0.8 ml

• (400, 0.2) ⇒ 400 mb, 0.2 ml

• (600, 0.15) ⇒ 600 mb, 0.15 ml

• (760, 0.1) ⇒ 760 mb, 0.1 ml

The points represented as (x, y) are referred to as ordered pairs, indicating that the sequence is significant: the first number denotes the independent variable whereas the second denotes the dependent variable.

Thus, for the point (90, 0.9), 90 indicates a pressure of 90 mb and 0.9 indicates a volume of 0.9 ml.

To find (600, 0.15), since the horizontal increments are valued at 0.1, you should place the second coordinate of the point between the marks corresponding to 0.1 and 0.2 ml.

This allows you to accurately plot each point on the graph.

The equation representing the reaction between sodium bicarbonate and hydrochloric acid is as follows:

The substances and combine in a 1:1 ratio. Therefore, we calculate the quantity of sodium bicarbonate and its molar mass to determine the moles formed.

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We also recognize that the stoichiometric proportions are 1:1:1:1:1, which leads to the conclusion that the moles of equal 24.977 moles.

Next, we apply the ideal gas equation , where P denotes pressure, V refers to volume, R is the gas constant, and T represents the temperature in kelvins. We rearrange to solve for V

The final answer should be expressed in liters, , hence

A. iodine C. fluorine F. bromine Explanation: Ionic bonds primarily form between metals and non-metals, typically where there exists a significant difference in electronegativity between the constituent atoms. This situation results in one atom seeking to gain electrons while the other donates them. For zinc to form a compound in a 1:2 ratio, its combining power must align accordingly. The prevalent oxidation state of zinc is +2. The other combining atoms must also possess the capacity to accept two electrons. The halogens fit perfectly here, as they require only one electron to achieve stability and are highly electronegative. Hence, if two halogens combine with zinc, they will result in an ionic bond. The relevant halogens include fluorine, chlorine, bromine, iodine, and astatine which will yield compounds: ZnF₂, ZnBr₂, and ZnI₂.

Q is determined to be 12.38. The Nernst equation is expressed as Ecell = E°cell - (2.303RT/nF) log Q, where Q represents the reaction quotient. The reaction quotient Q is calculated by taking the product of the products' concentrations divided by the product of the reactants' concentrations. For an electrochemical cell, Q is the concentration ratio of the solution at the anode compared to that at the cathode. Consequently, Q = [anode]/[cathode], specifically Q = 0.052/0.0042, arriving at a value of Q = 12.38.

The compound is acetone ( CH₃-CO-CH₃)

Explanation:

1) Acetone is represented as CH₃-CO-CH₃.

2) This is a molecule formed by covalent bonds.

3) When it dissolves, compounds with covalent bonds remain as individual molecules, indicating that the primary species in the solution are the molecules themselves, which are surrounded (solvated) by water molecules.

In contrast, ionic compounds ionize. For example, when NaCl dissolves in water, it completely breaks down into ions, hence the predominant species are the ions Na⁺ and Cl⁻, rather than the NaCl formula.

This leads to the conclusion that: when acetone dissolves in water, the primary components are the acetone molecules (there is no need to mention that water molecules are in the solution, as that isn't the question's focus).