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Reil
10 days ago
5

A ship maneuvers to within 2500 m of an island's 1800 m high mountain peak and fires a projectile at an enemy ship 610 m on the

other side of the peak, as illustrated in Figure 3-29. If the ship shoots the projectile with an initial velocity of v = 248 m/s at an angle of θ = 74°, how close to the enemy ship does the projectile land?
Physics
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When you apply the torque equation ∑τ = 0 to an object in equilibrium, the axis about which torques are calculated:
Softa [3030]

Answer:

option D.

Explanation:

The correct choice is option D.

For an object in equilibrium, the torque measured at any point will be zero.

An object is deemed to be in equilibrium when the net moment acting on it equals zero.

If the object experiences a net moment not equal to zero, it will rotate and will not remain stable.

3 0
4 months ago
An elevator is moving upward at 1.20 m/s when it experiences an acceleration of 0.31 downward over a distance of 0.75m. What wil
kicyunya [3294]
<span>Details: Initial velocity, Vi = 1.20 m/s, acceleration, a = 0.31 m/s², distance, Δx = 0.75 m, final velocity, Vf =?

To find Vf, we use the formula: Vf = sqrt (Vi^2 + 2aΔx) = sqrt ((1.20 m/s)^2 + 2(0.31 m/s² * 0.75 m))
= 0.99 m/s</span>
5 0
4 months ago
Read 2 more answers
The x coordinate of an electron is measured with an uncertainty of 0.200 mm . What is vx, the x component of the electron's velo
Sav [3153]

Answer:

The electron's velocity in the x direction is measured at 57.9 m/s

Explanation:

The uncertainty in the x position of the electron is Δx = 0.200 mm = 0.2 x 10⁻³ m

Let vₓ denote the x component of the electron's velocity.

The momentum's uncertainty in the x component is given by:

Δpₓ = mΔvₓ

where m represents the electron's mass.

The uncertainty in the velocity's x component is set at 1%, or 0.01.

Thus, we can rewrite the previous equation as:

Δpₓ = 0.01mvₓ....(1)

The fundamental principle of uncertainty is:

\Delta x\Delta p_{x} = \frac{h}{2\pi }....(2)

Using equations (1) and (2),

\Delta x\times0.01m v_{x} = \frac{h}{2\pi }

Substituting 0.2 x 10⁻³ m for Δx, 9.1 x 10⁻³¹ kg for m, and 6.626 x 10⁻³⁴ m²kg/s into the formula yields:

0.2\times10^{-3} \times0.01\times9.1\times10^{-31}\times v_{x} = \frac{6.626\times10^{-34} }{2\pi }

vₓ = 57.9 m/s

8 0
3 months ago
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