4. How does the kinetic theory of gases explain the weather changes happening in the troposphere? You can also research on the I

Ethanol, with the formula C2H5OH, is also referred to as Ethyl alcohol.

Explanation:

• The interaction between oil and sodium hydroxide (NaOH) is recognized as the Saponification process.

• A combination of ethanol and water yields a fully homogeneous solution, miscible in all proportions.

• We use a mixture of ethanol and water for the Saponification because it prevents the fat from reacting with atmospheric oxygen.

• This mixture is advantageous as it exhibits lower polarity than water, aiding in the dissolution of non-polar fats, thereby facilitating reaction with sodium hydroxide.

Answer: 1.31M

Explanation:

V1 = 10mL

C1 = 8.5M

V2 = 65mL

C2 =?

Using C1V1 = C2V2

10 x 8.5 = C2 x 65

C2 = (10 x 8.5 ) /65

C2 = 1.31M

Answer:

45727g

Explanation:

The overall ionic reaction can be described as follows:

CrO42^- + 3 Fe2^+ + 8 H2O ------> Cr(OH)^3(s) + 3 Fe(OH)^3(s) + 4 H^+.

The amount of wastewater processed each day is specified as 60m^3/h, with the concentration of chromium in the wastewater recorded at 4.0 mg/L, and the allowable discharge concentration is set at 0.1 mg/L.

Step one: Convert m^3/h to L/h. Therefore, 60 m^3/h × 1000 dm^3 = 60000 L/h.

Step two: Calculate the amount of chromium consumed.

The amount of chromium utilized = { 60,000 × ( 4.0 - 0.1) } ÷ 1000 = 234 g.

Step three: Calculate the masses of Cr(OH)3 and Fe(OH)3.

The moles of chromium = 234/52 = 4.5 moles.

Molar mass of Cr(OH)3 = 103 g/mol and the molar mass of Fe(OH)3 = 106.8 g/mol.

Thus, the mass of Cr(OH)3 = 4.5 × 103 = 463.5 g.

And, the mass of Fe(OH)3 = 13.5 × 106.8 = 1441.8 g.

Consequently, the total equals 463.5 g + 1441.8 g = 1905.3 g.

Step four: Calculate the amount of particulate matter generated each day.

The total particulate matter produced daily = 24 × 1905.3 = 45727g.

The resulting temperature is 46.5°C.

Details:

According to Charles's law, the volume of gas, while maintaining constant pressure, correlates directly with temperature in Kelvin.

The formula representing Charles's law is expressed as follows:

We need to determine T2, thus:

V1 = 736 ml = 0.736 L

T1 = 15 ° C

V2 = 2.28 L

Substituting the values gives us:

T2 =

    = 46.5°C

It is evident that as the volume increases, the temperature also rises.