Answer:
15.71g
Explanation:
The combustion equation that applies to hydrocarbons is
CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O
In the case of octane, C8H18:
C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O
C8H18 + 50/4 O2 = 8CO2 + 9H2O
C8H18 + 25/2 O2 = 8CO2 + 9H2O
2C8H18 + 25 O2 = 16 CO2 + 18H2O (this is the balanced equation)
From this balanced reaction,
2 x 22.4 L of octane generates 16 [ 12 + (16 x 2)] of carbon dioxide
That means,
44.8 L of octane generates 704g of carbon dioxide
Thus, for 1L of octane, it produces 1 L x 704g/44.8 L = 15.71g of carbon dioxide
Consequently, 15.71g of carbon dioxide is produced from the complete combustion of 1 L of octane.