Answer:
Explanation:
Diethyl malonate possesses greater acidity compared to monocarbonyl substances (pKa=13) because its alpha hydrogens are linked to two carbonyl groups. Consequently, the malonic ester can be readily changed into its enolate ion by reacting it with sodium ethoxide in ethanol. When the malonic ester undergoes alkylation, a hydrogen atom in the alpha position becomes acidic, permitting another round of alkylation to yield a dialkylated malonic ester.
In this scenario, when diethyl malonate interacts with urea in the presence of sodium ethoxide base, the second alkylation step occurs within the molecule, producing a cyclic compound known as barbituric acid.
The solution to your inquiry is: c = a + b - d. In the chemical equation aA + bB → cC + dD, c may take any value from 1 to however many are needed for the equation to maintain its balance. For instance, if we consider c + d = a + b, we can express c as a + b - d. If we assign values a = 1; b = 3, and d = 2, then c equals 1 + 3 - 2, resulting in c = 2, and so forth.
One electron is involved. Explanation: In redox reactions, determining the equivalents requires knowledge of the number of transferred electrons. In this specific case, one equivalent corresponds to a transfer of a single electron.
Answer:
To achieve the desired outcome, 8.55 mL of NaOH is necessary.
Explanation:
Considering that:
the weak acid has a mass of 0.4 g
and a molecular weight of 234 g/mol
so, the number of moles of the weak acid is calculated as 0.4 g/234 g/mol = 0.00171 mole
To convert half of the weak acid (WA) to conjugate base (CB), we must add NaOH.
Thus, [WA]=[CB] 0.00171/2 = 8.55×10⁻⁴ mole of NaOH required
Further, knowing that the concentration of NaOH is 0.10 M
the volume needed to achieve this result can be calculated as follows:
= 
= 8.55 mL of NaOH is necessary
Chromatography is the method recommended for separating the two amino acids, glycine and alanine.
