Response:
a) 4 kg/s
b) 99.61 °C
Rationale:
Refer to the pictures provided.
A 10-ft-long simply supported laminated wood beam consists of eight 1.5-in. by 6-in. planks glued together to form a section 6 i
n. wide by 12 in. deep. The beam carries a 9-kip concentrated load at midspan. Which point has the largest Q value at section a–a?
1 answer:
Point B is where 
shows the highest Q value at section a–a. The missing diagram that was supposed to accompany this question can be found in the attached file. Based on the given information, we must identify the point with the greatest Q value at section a–a. To achieve this, we're working with the attached image. The image reveals that there are 8 blocks stacked vertically on the right-hand side, totaling 12 inches; thus, each block measures 1.5 inches in height. Additionally, the blocks are divided into sections marked as A, B, C, and D. For point A, we use the formula Q representing the moment of Area A. For point B, we set Q as the moment of Area B, and similarly for points C and D. However, point D has no area, resulting in a moment of 0.
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Answer:
Volume change percentage is 2.60%
Water level increase is 4.138 mm
Explanation:
Provided data
Water volume V = 500 L
Initial temperature T1 = 20°C
Final temperature T2 = 80°C
Diameter of the vat = 2 m
Objective
We aim to determine percentage change in volume and the rise in water level.
Solution
We will apply the bulk modulus equation, which relates the change in pressure to the change in volume.
It can similarly relate to density changes.
Thus,
E = ................1
And ............2
Here, ρ denotes density. The density at 20°C = 998 kg/m³.
The density at 80°C = 972 kg/m³.
Plugging in these values into equation 2 gives
dV = 0.0130 m³
Therefore, the percentage change in volume will be
dV % = × 100
dV % = × 100
dV % = 2.60 %
Hence, the percentage change in volume is 2.60%
Initial volume v1 = ................3
Final volume v2 = ................4
From equations 3 and 4, subtract v1 from v2.
v2 - v1 =
dV =
Substituting all values yields
0.0130 =
Thus, dl = 0.004138 m.
Consequently, the water level rises by 4.138 mm.