Which sentences in this passage are true?

J(r) = Br. We know that the area of a small segment, dA, is represented as 2 π dr. Thus, I = J A and dI = J dA. Plugging in the values gives us dI = B r. 2 π dr which simplifies to dI= 2π Br² dr. Now, integrating the above equation: Given that B= 2.35 x 10⁵ A/m³, with r₁ = 2 mm and r₂ equal to 2 + 0.0115 mm, or 2.0115 mm.

Answer:

(a). The coefficient of permeability is .

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.

Explanation:

Given that,

Length = 175 mm

Diameter = 175 mm

Time = 90 sec

Volume= 405 cm³

We need to calculate the discharge

Using formula of discharge

Insert the values into the formula

(a). We will compute the coefficient of permeability

Applying the formula for permeability

Where, Q=discharge

l = length

A = cross-sectional area

h=constant head that causes flow

Plugging the value into the formula

The coefficient of permeability measures as .

(c). To ascertain the discharge velocity during the testing phase

Utilizing the discharge velocity formula

Substituting the values into the equation

The discharge velocity during the test measures 0.0187 cm/s.

Thus, (a). The coefficient of permeability is .

(b). The seepage velocity computes at 0.0330 cm/s.

(c). The observed discharge velocity during the test equals 0.0187 cm/s.

Answer:

The result is 2

Explanation:

When discussing the mechanical benefit of a lever, you divide the two values to obtain the right answer.  3/6 = 2