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2 months ago

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During an auto accident, the vehicle's air bags deploy and slow down the passengers more gently than if they had hit the windshi

eld or steering wheel. According to safety standards, the bags produce a maximum acceleration of 60 g, but lasting for only 36 ms (or less).
How far (in meters) does a person travel in coming to a complete stop in 36 ms at a constant acceleration of 60g?

1 answer:

ValentinkaMS [3.4K]2 months ago

7 0

Answer:

With an acceleration of 60g, equating to 60 times the force of gravity, an individual will move a distance of 0.38 m before coming to a full stop.

Explanation:

The peak acceleration of the airbag is 60 g and it lasts for 36 ms, which is 36/1000 s or 0.036 s.

To determine how far (in meters) a person travels while stopping in 36 ms at a steady acceleration of 60g, we can apply the equation of motion.

S = ut + 0.5at²

Where:

S = distance to stop

u = final velocity = 0 m/s

a = acceleration = 60g = 60 × 9.81

t = time = 36 ms

The equation introduces the required variables as follows:

S = 0×0.036 + 0.5×60×9.81×(0.036)² = 0.38 m.

During a 60g acceleration, an individual will cover a distance of 0.38 m before stopping completely.

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