What is the molarity of a solution that is made by adding 57.3 g of MgO to 500.0 mL of solution?

Answer:

Explanation:

Chlorine has an electron configuration of 2, 8, 7

Within the n = 3 shell, it has 7 electrons consisting of 2 in the s subshell and 5 in the p subshell. However, one of the p electrons shifts to the d orbital, altering the electronic configuration  to be as follows

 = 7

These orbitals such as sp³d hybridize, creating 7 degenerate orbitals where two orbitals are filled with electron pairs and three remain singly occupied by electrons (unpaired electrons).

2C6H14 + 13O2 ---> 6CO2 +14H2O

Calculating the molar mass of C6H14: M(C6H14)=12.011*6 +1.008*14 ≈ 86.17 g/mol

Thus, 86.17 g of C6H14 corresponds to 1 mole.

                                  2C6H14 + 13O2 ---> 6CO2 +14H2O
based on the equation        2 mol                            6 mol
according to the question    1 mol                            3 mol

To determine M(CO2): M(CO2)= 12.011 + 2*15.999= 44.009 g/mol
Therefore, 3 mol CO2*44.009 g/1 mol CO2 ≈ 132.0 g CO2
Final answer: 132.0 g CO2