methane Express your answer as a condensed structural formula omitting all bonds (e.g CH3CH2CH3). nothing Request Answer Part B

Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO

The work done is 19.26 kJ.

The interaction between calcium carbonate and hydrochloric acid can be represented by the chemical equation,

    CaCO3 + 2HCl --> CaCl2 + H2O + CO2

Calcium carbonate has a molecular weight of 100 g/mol, while hydrochloric acid's molecular weight is 36.45 g/mol. According to the equation, 100 g of calcium carbonate reacts with 72.9 g of hydrochloric acid.

    x = (4 g HCl)(100 g CaCO3 / 72.9 HCl)
      x = 5.49 g

Final result: 5.49 g