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swat32
1 month ago
11

Determinación de pH Expresa las siguientes concentraciones de [H+ ] en función del pH • [H+] = 0.001 M • [H+] = 0.002 M • [H+] =

2.45X10-4 M • [H+] = 5.2X10-9 M • [H+] = 0.04 M
Chemistry
1 answer:
lorasvet [2.7K]1 month ago
8 0
• pH = 3.0 • pH = 2.70 • pH = 3.61 • pH = 8.28 • pH = 1.40 Explanation: The pH is a chemical measure indicating acidity or basicity levels in a solution. It is expressed as: pH = -log₁₀ [H⁺], referring to the negative logarithm of the H⁺ concentration. For the given H⁺ concentrations: • [H+] = 0.001 M leads to pH = -log(0.001M) = 3. • [H+] = 0.002 M results in pH = -log(0.002M) = 2.70. • [H+] = 2.45X10^-4 M gives pH = -log(2.45X10^-4 M) = 3.61. • [H+] = 5.2X10^-9 M results in pH = -log(5.2X10^-9 M) = 8.28. • [H+] = 0.04 M yields pH = -log(0.04M) = 1.40.
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Choice (3) is correct: they exhibit the same chemical properties. Both samples are under identical conditions, so their densities remain unchanged. Gram-formula mass is an intrinsic property of the substance and does not vary. The volume would change if the mass changes.
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1 month ago
the image above shows a chamber with a fixed volume filled with gas at a pressure of 1560 mmHg and a temperature of 445.0 K. If
VMariaS [2998]

Answer:

The new gas pressure within the chamber registers at 1,093.75 mmHg

Explanation:

The Gay-Lussac Law establishes a relationship between a gas's pressure and temperature when volume remains constant. This principle asserts that gas pressure is directly tied to its temperature: as temperature increases, pressure rises, and conversely, as temperature falls, pressure also diminishes. Therefore, the Gay-Lussac law can be depicted mathematically as:

\frac{P}{T} =k

Given an initial and final state of gas, we can apply the following formula:

\frac{P1}{T1} =\frac{P2}{T2}

In this scenario:

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<psubstituting:>

\frac{1560 mmHg}{445 K} =\frac{P2}{312 K}

Calculating:

P2=\frac{1560 mmHg}{445 K} *312K

P2=1,093.75 mmHg

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</psubstituting:>
7 0
3 months ago
How many liters of cane juice is needed to supply 5g sucrose if cane juice contains 12% sucrose
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Given parameters:

Mass of sucrose  = 5g

Density of sucrose  = 1.12g/mL

Percentage of sucrose per liter of cane juice  = 12%

Unknown:

Volume of cane juice required =?

We need to understand the relationship between volume and density. Density represents mass per unit volume.

Mathematically;

                Density  = \frac{mass}{volume}

Now, calculate the volume of sucrose;

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Since 12% of one liter of cane juice is sucrose,  

                    12% of  x  liter of cane juice  = 4.46 x 10⁻³L

                   Volume of cane juice  = 4.46 x 10⁻³ x \frac{100}{12}   = 0.037L

Volume of cane juice needed is  0.037L

   

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2 months ago
An industrial manufacturer wants to convert 175 kg of methane into HCN. Calculate the masses of ammonia and molecular oxygen req
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Context:

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