A 1.0-m-long copper wire of diameter 0.10 cm carries a current of 50.0 A to the east. Suppose we apply to this wire a magnetic f

Answer:3.87*10^-4

Explanation:

To determine the mass reduction, delta mass Xe, of the xenon nucleus due to its decay, we first use the provided wavelength of the gamma radiation to calculate its frequency via c = freq*wavelength.

From C=f*lambda we set up: 3*10^8=f*3.44*10^-12.

Solving gives frequency F=0.87*10^20 Hz.

Next, we calculate the emitted energy using the equation E=hf, which translates to E=f*Planck's constant.

Thus, E=0.87*10^20*6.62*10^-34, resulting in E=575.94*10^(-16).

This energy is then converted from joules to MeV.

Utilizing the formula E=mc^2, with c^2 = 931.5 MeV/u, enables us to find the reduction in mass, yielding

3.87*10^-4 u.

Answer:

  v₂ = v/1.5 = 0.667 v

Explanation:

We will apply the conservation of momentum for this problem, defining a system that includes both students and their carts; the forces during contact are considered internal, ensuring momentum is conserved.

Initial momentum before the push

p₀ = 0

Final momentum after the push yields

    = m₁ v₁ + m₂ v₂

   0 = m₁ v₁ + m₂ v₂

Substituting yields

   v₂ = v / 1.5