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Sedbober
7 days ago
11

Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici

ent is "1."
CS2 +
Cl2 →
CCl4 +
S2Cl2
Physics
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Find the net electric force that the two charges would exert on an electron placed at point on the xx-axis at xx = 0.200 mm. Exp
Keith_Richards [3271]

Response:

Some details are lacking in the question; here’s the complete version: A -3.0 nC point charge is positioned at the origin, while a -5.0 nC point charge exists along the x-axis at x = 0.800 m. Determine the overall electric force that the two charges would have on an electron situated at 0.200 m along the x-axis.

Clarification:

Coulomb's law applies to solve this problem as illustrated in the accompanying file.

6 0
3 months ago
A transverse wave on a string has an amplitude A. A tiny spot on the string is colored red. As one cycle of the wave passes by,
serg [3582]

Answer: E. 2A

Explanation:

The amplitude (A) of a wave refers to the maximum displacement from its rest position. The peak value of the amplitude corresponds to the crest, while the lowest value represents the trough.

For a wave to complete a full cycle, it must travel back and forth from its displacement point.

<pIf the red-marked spot on the string completes one cycle, it indicates that it has traversed through the crest and the trough, which amounts to 2 amplitudes.

6 0
4 months ago
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier b
Maru [3345]

Answer:

The accurate equations are T-fg=ma and L-fg=0.

Options (A) and (C) are valid.

Explanation:

Given that:

Weight Fg = mg

Acceleration = a

Tension = T

Drag force = Fa

Vertical force = L

We are required to determine the correct relationships

Using the equilibrium equations

Horizontally,

The acceleration is a

T-Fd=ma...(I)

Vertically,

No acceleration occurs

w=L

mg-L=0

Substituting the value of mg

L-fg=0....(II)

Thus, the correct relationships are T-fg=ma and L-fg=0.

Options (A) and (C) are correct.

3 0
3 months ago
Imagine you derive the following expression by analyzing the physics of a particular system: a=gsinθ−μkgcosθ, where g=9.80meter/
Sav [3153]

Answer:

Explanation:

Examining the derived equation reveals

a=gsinθ−μkgcosθ

All components in this formulation are accurate, but further simplification is achievable.

We can explore additional simplification within the equation.

<pby analyzing="" the="" right="" side="" we="" see="" that="" gravity="" is="" a="" common="" factor="" on="" both="" terms="" hence="" can="" it="" out:="">

This makes option a incorrect, as further simplifications yield

a=g(sinθ−μkcosθ)

Option b is valid and represents the optimal choice.

Since we are provided with g=9.8m/s²

we can also input this into option a

<presulting in="">

a=9.8m/s²(sinθ−μkcosθ)

Option C also holds but is less preferred as it substitutes the gravity value directly without prior simplification.

The optimal form would be

a=9.8m/s²(sinθ−μkcosθ)

Thus, the best choice is B.

</presulting></pby>
8 0
3 months ago
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