The expression represents the cost of Janelle’s cell phone bill, where m represents the number of minutes of use.

The three equivalent numerical expressions are:

Solutions to create three numerical expressions equivalent to (0.0004). (0.005)

<span>With AB tangent at D, where AD = OD = 4
, triangle OAD forms a right angle with sides measuring 4 and 4.
So, the area of triangle OAD is computed as 1/2 * 4 * 4 = 8

The angles AOD and DAO equal 45 degrees.
Therefore, the area of circular sector OCD is calculated as the area of circle O multiplied by 45/360
= pi * 4 * 4 * 45/360
= 2pi

The shaded area ACD results from the triangle OAD minus the area of circular sector OCD
= 8 - 2pi
= 1.72




</span>

Answer:

Step-by-step explanation:

<pGreetings!

a. The variable X represents the height of a Goomba, which follows a normal distribution with a mean of μ= 12 inches and a standard deviation of δ= 6 inches.

To find the probability that a Goomba picked at random has a height between 13 and 15 inches, you express it as:

P(13≤X≤15)

Considering that standard normal probability tables provide cumulative values, you can express this range as the cumulative probability up to 15 minus the cumulative probability up to 13. You'll first need to standardize these variable heights to obtain corresponding Z values:

P(X≤15) - P(X≤13)

P(Z≤(15-12)/6) - P(Z≤(13-12)/6)

P(Z≤0.33) - P(Z≤0.17)= 0.62930 - 0.56749= 0.06181

b. Now we have Y as the variable indicating the height of a Koopa Troopa. This variable also follows a normal distribution, with a mean μ= 15 inches and a standard deviation δ=3 inches.

The query concerns the probability that a Koopa Troopa stands taller than 75% of Goombas.

First step:

You need to determine the height of a randomly chosen Koopa Troopa that exceeds 75% of the Goomba population.

This entails determining the value of X corresponding to the limit below which 75% of the population falls, denoted by:

P(X ≤ b)= 0.75

Step 2:

Search the standard normal distribution for the Z value that has 0.75 beneath it:

Next, you will reverse the standardization to solve for "b"

Z= (b - μ)/δ

b= (Z*δ)+μ

b= (0.674*6)+12

b= 16.044 inches

Step 3:

With the height that identifies a Koopa Troopa taller than 75% of the Goomba population determined, compute the probability of selecting that Koopa Troopa:

P(Y≤16.044)

This time, utilize the Koopa’s average height and standard deviation to find the probability:

P(Z≤(16.044-15)/3)

P(Z≤0.348)= 0.636

The likelihood of randomly selecting a Koopa Troopa that is taller than 75% of Goombas is 63.6%

I hope this information is useful!

1.55 CHF =?1 The price of the watch in Geneva is 1.55 CHF =?1 while 193 CHF =??1, which can be designated as x. Setting up a proportion, we cross-multiply, resulting in 1.55x = 193. Dividing by 1.55, we find x = 124.52 in x units. However, Manchester merchants are pricing it at 143 x units, so the difference is 143 - 124.52 = 18.48 units more expensive in Manchester.