It is stated that, in a typical pulsed-field machine, the magnetic field rises from 0 T to 2.5 T within 200 μs. The change in the magnetic field and time interval are relevant here. The diameter is 2.3 cm, translating to a radius of 0.0115 m. As the magnetic field changes, an induced emf occurs within the ring, determined by: E = 5.19 volts. Thus, the induced emf in the ring equates to 5.19 volts, which is the sought solution.
As the parachutist is descending at a steady rate
we can conclude that

Acceleration indicates the change in velocity
given the constant velocity in this scenario

Thus, in this situation, we find the acceleration to be zero
It’s understood from Newton's second law

where a is equal to 0


Here, the force due to gravity
equals the force due to buoyancy
Hence, we can deduce

therefore

as such the upward force is counteracted by the downward force.
Answer:
d_total = 12 m
Explanation:
In this kinematics scenario illustrated in the graph provided, we determine the distance traveled over a 24-second duration.
The comprehensive distance can be calculated as follows:
d_total = d₁ + d₂ + d₃
Given that d₂ on the graph is level (v=0), its distance equates to zero, hence d₂ = 0.
The distance for d₁ is calculated as:
d₁ = 12 - 6 = 6 m
For distance d₃:
d₃ = 6 - 0 = 6 m
Thus, the overall distance covered is:
d_total = 6 + 0 + 6
d_total = 12 m