A cement factory emits 900 kilograms of CO2 to produce 1,000 kilograms of cement. A fully grown tree removes six kilograms of CO

Response:

Clarification:

Impulse is equal to change in momentum

mv - mu, where v and u represent the final and initial velocities during the surface impact

For the downward motion of the baseball

v² = u² + 2gh₁

= 2 x 9.8 x 2.25

v = 6.64 m / s

This becomes the initial velocity upon impact.

For the upward movement

v² = u² - 2gh₂

u² = 2 x 9.8 x 1.38

u = 5.2 m / s

This becomes the final velocity post-impact

change in momentum is

m ( final velocity - initial velocity )

.49 ( 5.2 - 6.64 )

=.7056 N.s.

Impulse exerted by the floor in the upward direction is

=.7056 N.s

Answer:

A. 456 seconds

Explanation:

Two students walk down a straight path in the same direction at constant velocities.

One has a velocity of 0.90 m/s

while the other moves at 1.9 m/s.

Each student covers a distance of 780 meters.

Our goal is to determine who is quicker and the additional time the slower student takes compared to the faster one.

For the student moving at 0.90 m/s, the time taken is .

Time=.

The time for the student at 0.90 m/s is

=.

This time calculates to 866.6 seconds.

Now for the student traveling at 1.9 m/s: their time is ,

which amounts to 410.5 seconds.

The second student, moving at 1.9 m/s, is faster than the one at 0.90 m/s.

The slower student takes 866.6 - 410.5 = 456.1 seconds longer.

Thus, the additional time for the slower student is 456 seconds.

Therefore, option A is correct.