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3 months ago

Give the symbols for 4 species that are isoelectronic with the telluride ion, te2-.

1 answer:

3 0

<span>Response: Chlorine has 17 electrons, thus, for 1+ and 2+ ions, we require elements with 18 and 19 electrons, which are argon and potassium: Ar+ and K 2+. For 1- and 2- ions, we need elements with 16 and 15 electrons, namely sulfur and phosphorus, represented as S- and P 2-. It’s important to note that + ions indicate electron loss, while - ions reflect electron gain.</span>

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myron is almost late for class and he is running quickly to arrive before the professor begins lecturing as he listen to the pro

inna [3103]

No established theory exists here.
Myron has presented a strong hypothesis to clarify his observations.
Alternative hypotheses could be:

-- An infected mosquito might have bitten him during his sleep, causing symptoms to manifest.

-- He may have consumed something for dinner that was a bit spoiled.

-- He might have had excessive alcohol at the fraternity party last night.

-- The air in the classroom could contain elevated levels of Carbon Dioxide.

-- His body might be responding to the physical exertion of rushing to class.

Currently, Myron has merely formulated a hypothesis.
He cannot draw any "conclusion" until he tests his hypothesis and demonstrates that similar outcomes consistently result from the same conditions. Testing his hypothesis may prove challenging, but unless he does so, he lacks a comprehensive theory.

In my view, while his hypothesis may indeed be valid, the most probable explanation for his experience is the recent physical strain from running to class. It’s crucial to note that I cannot convince anyone of this conclusion; my perspective is merely another hypothesis. Its validity holds no significance unless it undergoes testing.

6 0

3 months ago

An electron moves in a region where the magnetic field is uniform and has a magnitude of 80 μT. The electron follows a helical p

Softa [3030]

Answer:

3.4 x 10⁴ m/s

Explanation:

Analyze the circular path of the electron

B = magnetic field = 80 x 10⁻⁶ T

m = mass of an electron = 9.1 x 10⁻³¹ kg

v = speed in the radial direction

r = radius of the circular trajectory = 2 mm = 0.002 m

q = charge of an electron = 1.6 x 10⁻¹⁹ C

For the electron’s circular movement

qBr = mv

(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v

v = 2.8 x 10⁴ m/s

Now, consider the electron's movement in a straight line:

v' = speed in linear motion

x = distance traveled horizontally = 9 mm = 0.009 m

t = duration = $\frac{2\pi m}{qB}$ = $\frac{2\pi (9.1\times 10^{-31})}{(1.6\times 10^{^{-19}})(80\times 10^{-6})}$ = 4.5 x 10⁻⁷ sec

Using the formula

x = v' t

0.009 = v' (4.5 x 10⁻⁷)

v' = 20000 m/s

v' = 2 x 10⁴ m/s

The resultant speed is given by

V = sqrt(v² + v'²)

V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)

v = 3.4 x 10⁴ m/s

6 0

3 months ago

An engine performs 2700 J of work on a scooter. The scooter and rider have a combined mass of 150 kg. If the scooter started at

serg [3582]

According to the principle of energy conservation, the engine's work in moving the scooter is converted into the scooter's kinetic energy, represented as:

6 0

3 months ago

A small cork with an excess charge of +6.0µC is placed 0.12 m from another cork, which carries a charge of -4.3µC.

serg [3582]

A) 16.1 N

The force of electricity acting between the corks can be calculated using Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where

k represents Coulomb's constant

$q_1 = 6.0 \mu C=6.0 \cdot 10^{-6} C$ denotes the charge magnitude on the first cork

$q_2 = 4.3 \mu C = 4.3 \cdot 10^{-6}C$ indicates the charge magnitude on the second cork

r = 0.12 m is the distance separating the corks

By inserting the values into the formula, we arrive at

$F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(6.0\cdot 10^{-6}C)(4.3\cdot 10^{-6} C)}{(0.12 m)^2}=16.1 N$

B) Attractive

- when both are similarly charged (e.g. positive-positive or negative-negative), the force is repulsive

- when charges are of opposite signs (e.g. positive-negative), the resulting force is attractive

Cork 1 holds a positive charge

Cork 2 possesses a negative charge

C) $2.69\cdot 10^{13}$

The total charge of the negative cork is

$q_2 = -4.3 \cdot 10^{-6}C$

$e=-1.6\cdot 10^{-19}C$

$q_2 = Ne$

$N=\frac{q_2}{e}=\frac{-4.3\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=2.69\cdot 10^{13}$

D) $3.75\cdot 10^{13}$

The overall charge on the positive cork is

$q_1 = +6.0\cdot 10^{-6}C$

$e=-1.6\cdot 10^{-19}C$

$q_1 = -Ne$

$N=-\frac{q_1}{e}=-\frac{+6.0\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=3.75\cdot 10^{13}$

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6 0

3 months ago