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Illusion
9 days ago
12

Give the symbols for 4 species that are isoelectronic with the telluride ion, te2-.

Physics
1 answer:
Keith_Richards [2.2K]9 days ago
3 0
<span>Response: Chlorine has 17 electrons, thus, for 1+ and 2+ ions, we require elements with 18 and 19 electrons, which are argon and potassium: Ar+ and K 2+. For 1- and 2- ions, we need elements with 16 and 15 electrons, namely sulfur and phosphorus, represented as S- and P 2-. It’s important to note that + ions indicate electron loss, while - ions reflect electron gain.</span>
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The acceleration due to gravity for any object, including 1 washer on the string, is always assumed to be m/s2. The mass of 3 wa
Keith_Richards [2263]

Answer:

The force will rise in direct relation to the mass of the objects

Explanation:

The gravitational acceleration remains constant. It is measured in meters per second squared or m/s². The average value is 9.81 m/s², calculated from observations made on varying surfaces. In reality, the acceleration can vary based on the geographical shape of the Earth relative to the earth's magnetic field and gravitational force.

For instance, if a single washer weighs 20 kg, with the gravity at 9.81 m/s², the weight would be:

F = ma

  = 20 * 9.81\\= 196.2 N

If there are three washers, the total weight calculates as:

F = 3 * 20 * 9.81

  = 588.6 N

5 0
8 days ago
Read 2 more answers
Consult Conceptual Example 9 in preparation for this problem. Interactive LearningWare 6.3 also provides useful background. The
Keith_Richards [2263]

Answer:

11.56066 m/s

Explanation:

m = Mass of individual

v = Velocity of individual = 13.4 m/s

g = Gravitational acceleration = 9.81 m/s²

v' = Velocity of the individual after dropping

At the surface, kinetic and potential energy will equalize

\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{13.4^2}{2\times 9.81}\\\Rightarrow h=9.15188\ m

The cliff's height is 9.15188 m

Define fall height as h' = 2.34 m

\dfrac{1}{2}mv'^2+mgh'=mgh\\\Rightarrow v'=\sqrt{2g(h-h')}\\\Rightarrow v'=\sqrt{2\times 9.81(9.15188-2.34)}\\\Rightarrow v'=11.56066\ m/s

The person's speed is 11.56066 m/s

3 0
27 days ago
How many turns should a 10-cm long solenoid have if it is to generate a 1.5 x 10-3 t magnetic field on 1.0 a of current?
kicyunya [2264]

This problem can be solved using Ampere’s Law:

<span>Bh = μoNI </span>

In this equation:

B = Magnetic Field

h = length of the coil

<span>μo = permeability = 4π*10^-7 T·m/A</span>

N = number of coil turns

I = current

Given values are B = 0.0015T, I = 1.0A, h = 10 cm = 0.1m<span>

Utilizing Ampere's law to determine the number of turns:
This can be rearranged to:
<span>N = Bh/μoI</span>
N = (0.0015)(0.1)/(4π*10^-7)(1.0)
N = 119.4

</span>

<span>Final answer: 119.4 turns</span>

3 0
5 days ago
A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b
Keith_Richards [2263]
The amount of work performed by a system at consistent pressure is defined by the following equation:
W=p \Delta V = p (V_f - V_i)
where
p represents pressure
V_f as the final volume
V_i as the initial volume

Plugging the values given in this case into the formula gives us
W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm

Considering that 1 atm \cdot L = 101.3 J, the result for the work done becomes
W= 1.00 atm \cdot L = 101.3 J
8 0
9 days ago
Read 2 more answers
In an amusement park rocket ride, cars are suspended from 3.40-m cables attached to rotating arms at a distance of 5.90 m from t
ValentinkaMS [2425]

Answer:

The rotational angular speed is measured at 1.34 rad/s.

Explanation:

Considering the following parameters,

Length = 3.40 m

Distance = 5.90 m

Angle = 45.0°

We are tasked with finding the angular speed of rotation

Using the balance equation

Horizontal component

T\cos\theta=mg

T=\dfrac{mg}{\cos\theta}

Vertical component

T\sin\theta=m\omega^2 r

Substituting the tension value

mg\tan\theta=m\omega^2(d+L\sin\theta)

\omega=\sqrt{\dfrac{g\tan\theta}{(d+L\sin\theta)}}

Substituting the value into the equation

\omega=\sqrt{\dfrac{9.8\tan45.0}{5.90+3.40\sin45.0}}

\omega=1.34\ rad/s

Thus, the angular speed of rotation computes to 1.34 rad/s.

7 0
1 month ago
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