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2 months ago

How many electrons are transferred in the given redox reaction? Zn+2AgNO3⟶2Ag+Zn(NO3)2

Chemistry

1 answer:

eduard [2.7K]2 months ago

7 0

Response:

In this reaction, 2 electrons are transferred.

Justification:

Oxidation involves losing electrons by an atom, ion, or molecule. Conversely, reduction pertains to the gain of electrons by an atom, ion, or molecule.

In oxidation-reduction reactions, both oxidation and reduction occur simultaneously.

This means that redox reactions entail the transfer of electrons among chemical species. They are also referred to as electron transfer reactions due to the exchanged particle being the electron.

In this case:

Zn(s) ⇒ Zn²⁺(aq) + 2 e⁻

2 Ag⁺(aq) + 2 e⁻ ⇒ 2 Ag(s)

Thus, zinc metal donates two electrons to create zinc(II) ions, and each of the two silver ions gains an electron to form two silver atoms.

Consequently, Zn acts as a reducing agent (the reducing agent is the one that donates the electrons, oxidizing itself), while AgNO3 functions as an oxidizing agent (the oxidizing agent traps the electrons, reducing itself).

Ultimately, as noted, 2 electrons are transferred in this reaction.

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Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are

Tems11 [2777]

Answer:

Unfavorable reactions include Reaction A and Reaction B.

Favorable coupled reactions: Reactions B with C and Reactions A with C.

Net energy change:

For Reactions B and C: -14.2 kJ/mol

For Reactions A and B: 30.1 kJ/mol

For Reactions A and C: -16.7 kJ/mol

Explanation:

A reaction is considered thermodynamically favorable (or spontaneous) if ΔG is less than 0. Thus, the unfavorable reactions where -ΔG is greater than 0 are:

Reaction A and Reaction B.

In coupling Reaction C with Reaction B and Reaction A, the following equation is obtained:

ATP + fructose-1,6-phosphate ⟶ ADP + fructose-1,6-bisphosphate

ΔG equals 16.3 minus 30.5, resulting in -14.2 kJ/mol.

For the reaction ATP + glucose ⟶ ADP + glucose-6-phosphate, ΔG equals 13.8 minus 30.5, yielding -16.7 kJ/mol.

Overall, the coupled reaction of A and B results in a change of free energy of:

ΔG = 13.8 plus 16.3, which equals 30.1 kJ/mol.

4 0

2 months ago

93.2 mL of a 2.03 M potassium fluoride (KF) solution

alisha [2963]

Response:

1.98 M

Clarification:

Provided data

Starting volume (V₁): 93.2 mL

Starting concentration (C₁): 2.03 M

Water volume added: 3.92 L

Step 1: Convert V₁ to liters

Using the relationship 1 L = 1000 mL.

$93.2mL \times \frac{1L}{1000mL} = 0.0932 L$

Step 2: Calculate the final volume (V₂)

The final volume is the total of the initial volume and the added water volume.

$V_2 = 0.0932L + 3.92 L = 4.01L$

Step 3: Calculate the final concentration (C₂)

Utilizing the dilution rule.

$C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M$

3 0

2 months ago

Read 2 more answers

Use the periodic table to identify the molar mass of each element below. Answer without doing any calculations.

Tems11 [2777]

Response:

Beryllium (Be): 9.01 g/mol

Silicon (Si): 28.09 g/mol

Calcium (Ca): 40.08 g/mol

Rhodium (Rh): 102.91 g/mol

Justification:

8 0

2 months ago

Read 2 more answers

From the Bohr equation in the introduction, the calculated energy of an electron in the sixth Bohr orbit of a hydrogen atom is

VMariaS [2998]

Answer:

= - 0.38 eV

Explanation:

According to Bohr's equation for the energy corresponding to an electron in the nth orbital,

E = -13.6 $\frac{Z^{2} }{n^{2} }$

Where E represents energy level in electron volts (eV)

Z symbolizes the atomic number of the atom

n denotes the principal quantum number

For n = 6

⇒ E = -13.6 × $\frac{1^{2} }{6^{2} }$

= - 0.38 eV

I hope this information helps.

4 0

2 months ago