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Marina86
13 days ago
8

93.2 mL of a 2.03 M potassium fluoride (KF) solution

Chemistry
2 answers:
KiRa [2.8K]13 days ago
6 0
Hello, in this situation, the initial volume was 93.2 mL, which converts to L as follows. After adding 3.92 L of water, the total volume of the final solution will encompass the water volume added, as illustrated here. Consequently, the molarity of the diluted potassium fluoride solution will be as follows. Best regards.
alisha [2.8K]13 days ago
3 0

Response:

1.98 M

Clarification:

Provided data

  • Starting volume (V₁): 93.2 mL
  • Starting concentration (C₁): 2.03 M
  • Water volume added: 3.92 L

Step 1: Convert V₁ to liters

Using the relationship 1 L = 1000 mL.

93.2mL \times \frac{1L}{1000mL} = 0.0932 L

Step 2: Calculate the final volume (V₂)

The final volume is the total of the initial volume and the added water volume.

V_2 = 0.0932L + 3.92 L = 4.01L

Step 3: Calculate the final concentration (C₂)

Utilizing the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M

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