Answer:
A balloon will hold a gas volume of 45.0 L at a pressure of 1.35 atm and a temperature of 253 K.
Explanation:
Applying the Ideal Gas Law for the same gas amount, we have:

Parameters are given as follows:
V₁ = 25.0 L
V₂ =?
P₁ = 2575 mm Hg
To convert pressure to atmospheres: P (atm) = P (mm Hg) / 760
P₁ = 2575 / 760 atm = 3.39 atm
P₂ = 1.35 atm
T₁ = 353 K
T₂ = 253 K
Using the earlier formula, we derive:



By solving for V₂, we find:
V₂ = 45.0 L
A balloon will hold a gas volume of 45.0 L at a pressure of 1.35 atm and a temperature of 253 K.
Hello!
density = 2.67 g/cm³
volume = 30.5 mL
Thus:
Mass = density * volume
Mass = 2.67 * 30.5
Mass = 81.435 g