Assuming we start with a full standard deck of 52 and then draw 4 spades along with 1 card from a different suit, that leaves us with 47 cards still in the deck. We are hoping to draw another spade from these remaining cards. Initially, there were 13 spades, but after drawing five cards, 9 spades remain in the deck. The likelihood of pulling one of these 9 spades from the 47 cards is

In other words, we want to get any 1 of the available 9 spades while avoiding any of the other 38 non-spades, and we're drawing just a single card from the 47 cards total.
Answer:
15
Step-by-step explanation:
Oooooooonnnnnneeeeeeeemmmmmmmmiiiiilllllllliiiiieeee
Answer:
y 
y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction
Explicación paso a paso:
La ecuación cuadrática que tenemos es (4y - 3)² = 72
Debemos encontrar el valor de y.
Ahora, 4y - 3 = ± 6√2
⇒ 4y = 3 ± 6√2
⇒
y 
Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)
Answer:
10,088 pounds
Step-by-step explanation:
Provided data
103 bushels of apples
102 bushels of grapes
101 bushels of oranges
With the respective weight per bushel:
Apples = 32 pounds
Grapes = 25 pounds
Oranges = 42 pounds
The total weight can be calculated by summing the products of each type:
Total Weight: 103(32) + 102(25) + 101(42) = 10,088 pounds