Ask question

Ask question

All categories

3 months ago

5

What is the specific heat of an unknown metal if 1.67 kcal of energy are required to raise the temperature of 79.2 g sample of t

he metal by 63.3 degrees celsius

2 answers:

lions [2.9K]3 months ago

8 0

Answer:

The specific heat of the unknown metal registers at 0.333 cal/g°C

Explanation:

Step 1: Given data

1.67 kcal of heat is needed

Metal mass = 79.2 grams

Temperature increment = 63.3 °C

Step 2: To determine the specific heat of the metal

Q = m*c*ΔT

⇒ where Q = the energy applied = 1.67 kcal = 1670 cal

⇒ m = metal mass = 79.2 grams

⇒ c = specific heat to be calculated

⇒ ΔT = temperature change = 63.3 °C

1670 cal = 79.2 grams * c * 63.3 °C

c = 0.333 cal/g*°C

<pThus, the specific heat of the unknown metal is 0.333 cal/g°C

VMariaS [2.9K]3 months ago

4 0

Answer:

The solution to your inquiry is C = 0.000333 kcal/g°C

or C = 0.333 cal/g°C

Explanation:

Data

Q = 1.67 kcal

mass = 79.2 g

ΔT = 63.3°C

Formula

Q = mCΔT

Solving for C

C = Q/mΔT

Substituting values

C = 1.67/(79.2 x 63.3)

Simplifying

C = 1.67 / 5013.4

Final Result

C = 0.000333 kcal/g°C

or C = 0.333 cal/g°C

You might be interested in

If you were given a sample of a cotton ball and a glass stirring rod with identical mass (ex: 5.0 g), which sample would contain

Anarel [2989]

Answer:

The sample with more oxygen atoms is a glass stirring rod.

Explanation:

Referring to the periodic table,

the glass stirring rod is composed of Silicon dioxide whereas the cotton ball is made of cellulose.

The molar mass of the glass stirring rod $SiO_{2}$ = 60.08 grams/mole.

The molar mass of the cotton ball $C_{6} H_{10}O_{5}$ = 162.09 grams/mole.

Considering the total number of molecules for oxygen is 32,

therefore,

In the glass stirring rod,

oxygen atoms contained in 5g = $\frac{32}{60.07} \times 5$

= 2.66 g of oxygen

= $\frac{1}{16} \times 2.66$

= 0.16625 moles

= 0.16625 x $6.023\times 10^{23}$

= $1.001 \times10^{23}$ atoms

In the cotton ball,

oxygen atoms contained in 5g = $\frac{80}{162.09} \times 5$

= 2.467 g of oxygen

= $\frac{1}{16} \times 2.467$

= 0.15418 moles

= 0.15418 $\times 6.023 \times 10^{23}$

= 0.928 $\\ \times10^{23}$

Thus, the glass stirring rod has a greater quantity of oxygen atoms.

4 0

4 months ago

a nurse practitioner orders Medrol to be given 1.5 mg/kg of body weight. if a child weighs 72.6lb and the available stock of Med

KiRa [2933]

The amount to administer to the child is 2,469 mL.
To convert to kilograms (kg), the child's weight in pounds (lb) is multiplied by 0.45359237: m(child) = 72.6 · 0.045359237 = 32.93 kg.
To find m(Medrol), the child's mass in kilograms is multiplied by 1.5 mg/kg.
Thus, m(Medrol) = 32.93 kg · 1.5 mg/kg = 49.39 mg.
The concentration of Medrol is d(Medrol) = 20.0 mg/mL.
To find the volume of Medrol needed, use V(Medrol) = m(Medrol) ÷ d(Medrol).
So, V(Medrol) = 49.39 mg ÷ 20 mg/mL = 2,469 mL.

8 0

3 months ago

A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista

eduard [2782]

Details:

The equation to calculate work done is defined as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

where, k = proportionality constant = $8.99 \times 10^{9} Jm/C^{2}$

$q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C$

$q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C$

d = separation distance = 0.45 nm = $0.45 \times 10^{-9} m$

Now we will insert the given values into the formula above to compute the work done as follows.

W = $-k \frac{q_{1}q_{2}}{d}$

= $\frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}$

= $3.68 \times 10^{-18} J$

Thus, we can conclude that the work needed to increase the distance between the two ions to infinity is $3.68 \times 10^{-18} J$ .

7 0

3 months ago

A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is

castortr0y [3046]

Answer: The overall width of a crystal measures 1.65 mm.

Explanation:

Horizontal distance separating the two molecules is 16.5 nm.

Width of the $10^5$ molecules: $16.5 nm\times 10^5=16.5\times 10^5 nm$

$1 nm=10^{-6} mm$

The overall width of a crystal measured in millimeters= $16.5\times 10^5\times 10^{-6} mm=1.65 mm$

The overall width of a crystal is 1.65 mm.

7 0

4 months ago

Read 2 more answers

Hitesh wants to learn swimming. He brought swimming costumes and a cap. What kind of material should these be made of and why?

alisha [2963]

Answer:

Nylon and Spandex (Lycra).

Explanation:

These materials are designed to fit the body, with nylon drying more quickly than other types of fabrics, and Spandex being commonly found in swimming and sports apparel due to its elastic qualities. Both fabrics also wick moisture away and dry rapidly.

With high capacity and enhanced flexibility, nylon and Spandex provide a snug fit to the body and can retain their shape during various activities, making them ideal for swimming.

This explains why these materials are suitable based on the situation given.

3 0

4 months ago