Answer: The number of sulfur dioxide molecules present is 1.27·10²³.
Calculating: m(SO₂) equals 13.5 g.
Using the formula n(SO₂) = m(SO₂) ÷ M(SO₂).
This gives n(SO₂) = 13.5 g ÷ 64 g/mol.
Resulting in n(SO₂) = 0.21 mol.
Subsequently, N(SO₂) = n(SO₂) ·Na.
Therefore, N(SO₂) = 0.21 mol · 6.022·10²³ 1/mol.
Ultimately, N(SO₂) equals 1.27·10²³.
Where n represents amount of substance.
M refers to molar mass.
Na is Avogadro's number.
First scenario:
IV: soda, gatorade, orange juice, and water
DV: state of the liquids listed above
Control: freezer and ice tray
Second scenario:
IV: laundry detergent, water
DV: cleanliness of the squares post-wash
Control: chocolate, cloth type, cloth squares
Third scenario:
IV: type of water used, pea plant
DV: growth of the pea plant
Control: pots and daily water amount for the plant
Answer:
The force is 38503.5N.
Explanation:
From the problem, we determine:
P (pressure) = 5.00 atm.
Next, to find the force in Newtons (N), we must convert 5 atm into N/m², as shown:
1 atm equals 101325 N/m².
So, 5 atm equals 5 x 101325 = 506625 N/m².
A (the piston area) = 0.0760 m².
Pressure signifies force per unit area, mathematically represented as
P = F/A.
From this, we find F = P × A.
F = 506625 × 0.0760.
Therefore, F = 38503.5N.
Thus, the piston experiences a force of 38503.5N.
Answer:
0.5 g/mL----- will float
1.0 g/mL---- will float
2.0 g/mL----- will sink
Explanation:
Objects with a density less than or equal to that of water will float due to having a lower mass, while objects with a density exceeding that of water will sink because their mass is greater than that of water. Thus, objects with a density of 0.5 g/mL and 1.0 g/mL will float since they are less dense than water (1 g/mL), whereas an object with a density of 2.0 g/mL will sink.
Specific heat refers to the quantity of heat a material can absorb or release to alter its temperature by one degree Celsius. To calculate specific heat, we apply the equation for the heat absorbed by the system. The heat taken in or released by a system can be expressed by multiplying the mass of the substance by its specific heat capacity and the change in temperature. The formula is:
Heat = mC(T2-T1)
By substituting the provided values, we can find C, the specific heat of the substance.
2510 J = 0.158 kg (1000 g / 1 kg)(C)(61.0 - 32.0 °C) C = 0.5478 J/g°C
