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SCORPION-xisa
18 days ago
7

The properties of two elements are listed below. Element Atomic radius (pm) Ionic radius (pm) First ionization energy (kJ/mol) E

lectron affinity (kJ/mol) Electronegativity Br 114 195 1140 –325 3.0 K 243 152.2 418.8 –48.4 0.82 Which prediction is supported by the information in the table? K will give up an electron more easily than Br. Both K and Br will have the same pull on electrons. K will have a smaller size in comparison to Br. Both K and Br will produce ions of the same size.
Chemistry
2 answers:
lions [2.7K]18 days ago
5 0

Examining the details in the table alongside the provided claims, it suggests that potassium (K) will readily surrender electrons compared to bromine (Br)

Ionization energy signifies the energy needed to remove an electron from an atom or ion. For potassium, the first ionization energy is 418.8 kJ/mol, while for bromine, it stands at 1140 kJ/mol. Hence, the ionization energy of bromine is significantly greater than that of potassium, reinforcing the belief that K will more easily part with an electron than Br.

Alekssandra [2.8K]18 days ago
3 0
The first choice might be correct. I'm sincerely sorry if I am mistaken!

FIRST OPTION (A)(1)
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A water tank can hold 1 m3 of water. When it’s empty, how much liters is needed to refill it?
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Response: 1000

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1 month ago
How much CO2 (L) is produced when 2.10 kg of sodium bicarbonate reacts with excess hydrochloric acid at 25.0 °C and 1.23 atm? A)
KiRa [2853]

The equation representing the reaction between sodium bicarbonate and hydrochloric acid is as follows:

NaHCO_3_(_s_) + HCl_(_a_q_) \implies NaCl_(_a_q_) + CO_2_(_g_) + H_2O_(_l_)

The substances NaHCO_3 and HCl combine in a 1:1 ratio. Therefore, we calculate the quantity of sodium bicarbonate and its molar mass to determine the moles formed.

NaHCO_3_M_r = 22.99 + 1.008 + 12.011+ 3 \times 16.0= 84.01 g/mol.

2.1kg\ NaHCO_3 \times \frac{1000g}{kg} \times \frac{mol}{84.01g/mol} = 24.997\ mol.

We also recognize that the stoichiometric proportions are 1:1:1:1:1, which leads to the conclusion that the moles of CO_2 equal 24.977 moles.

Next, we apply the ideal gas equation PV=nRT, where P denotes pressure, V refers to volume, R is the gas constant, and T represents the temperature in kelvins. We rearrange to solve for V

PV= nRT \implies V= \frac{nRT}{P}= \frac{ 24.997\ mol \times 8.2507m^3\ atm \times 298.15K }{mol \times K \times 1.23 atm} = 49967\ m^3

The final answer should be expressed in liters, 1L = 1000\ m^3, hence

49967\ m^3 \times\frac{L}{1000\ m^3} =49.97L\ CO_2\ produced

6 0
22 days ago
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The correct equation is (C) H3O+(aq) + C2H3O2−(aq) -> HC2H3O2(aq) + H2O(l). A buffer system is composed of a weak acid and its corresponding salt, effectively stabilizing the pH levels within a solution. The buffer works by adjusting the concentrations of the conjugate acid and base, maintaining the pH constant.
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5 days ago
In a chemical reaction, 300 grams of reactant A are combined with 100 grams of reactant B. Both A and
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I expect the product's mass to be 400 grams. This belief stems from the law of conservation of mass, which states that mass can neither be created nor destroyed. In a sealed system, the mass of the reactants equals the mass of the products. Therefore, since the total mass of the reactants is 400 grams, the resulting mass of the products must also be 400 grams

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Answer:

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Explanation:

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