A 5.00 kilogram mass is traveling at 100 meters per second. Determine the speed of the mass after an impulse of 30 Newton * seco

1) The wave's period remains constant across different media

2) The wave's velocity varies depending on the medium it travels through

3) As a wave transitions between media, its speed, direction, and wavelength can change, while its frequency stays unchanged

Clarification:

1)

The period of a wave signifies the duration it takes for one full oscillation.

The wave's period is the inverse of its frequency:

where

T denotes the period

f is the frequency

The provided table illustrates that the frequency remains consistent across the three media; hence, the period is unchanged as it solely relies on frequency. We can compute it as we know that

f = 350 Hz

thus the period equals

2)

The velocity of a wave can be derived from the wave equation:

where

f indicates the frequency

is the wavelength

<pin the="" first="" medium="">

, resulting in a speed of

In the second medium,

, leading to a speed of

In the third medium,

, showing a speed of

As a result, we conclude that the wave's speed varies with the medium.

3)

<pwhen a="" wave="" shifts="" from="" one="" medium="" to="" another="" the="" following="" occurs:="">

- The wave's direction alters. Specifically, if the subsequent medium is of greater optical density, the wave bends towards the normal; conversely, it bends away if the second medium is of lesser optical density.

- The wave's speed is affected. The wave decelerates in media with higher optical density and accelerates in those with lower optical density.

- The wave's frequency remains unchanged.

- Ultimately, the wave's wavelength is modified. If moving into a medium of greater optical density, the wavelength decreases, while it increases in one of lower optical density.

Discover more about waves here:

</pwhen></pin>

Answer:

F=126339.5N

Explanation:

To compute the force required to escape, a free-body diagram for the hatch must be drawn. We will equate the downward and upward forces, thus applying the following equation:

Fw=W+Fi+F

where

Fw=   force or weight exerted by the water column above the submarine.

To calculate Fw, we can use:

Fw=h. γ. A

h=height

γ= specific weight of seawater = 10074N / m ^ 3

A=Area

Fw=28x10074x0.7=197467N

w represents the hatch weight = 200N

Fi denotes the internal pressure force in the submarine, which is 1 atm = 101325Pa. We can calculate this force using:

Fi=PA=101325x0.7=70927.5N

Finally, the force needed to open the hatch is determined by the original equation:

Fw=W+Fi+F

F=Fw-W+Fi

F=197467N-200N-70927.5N

F=126339.5N

Response:

The question is not fully provided; here is the complete context:

Gravity's acceleration on the moon is 1.6 m/s², roughly one-sixth that of Earth's. What is the accurate description of an object's weight on the moon?

A. An object on the moon is lighter by a factor of 1/6 compared to Earth.

B. An object on the moon is heavier by a factor of 1/6 compared to Earth.

C. An object on the moon is six times lighter than on Earth.

D. An object on the moon is six times heavier than on Earth.

The correct choice is:

An object on the moon is six times lighter than on Earth. (C)

Explanation:

The acceleration resulting from gravity indicates how a gravitational force impacts an object, causing it to accelerate. This is a vectorial quantity because it possesses both magnitude and direction, measured in the unit of m/s². On Earth, this gravitational acceleration is represented by the letter g and its value is approximately 9.8m/s².

The larger size of the Earth in comparison to the moon causes its gravitational acceleration to be about six times greater than that of the moon, resulting in the moon's gravitational acceleration being approximately 1.6m/s².

Next, weight refers to the product of mass and gravity's acceleration. This reflects the gravitational pull acting upon a mass, which is also measured in Newtons, similar to force.

Weight = m × g (N)

From the weight formula, we can see that weight corresponds directly to mass and gravitational acceleration:

weight ∝ mass;

weight ∝ gravitational acceleration.

This implies that if gravitational acceleration increases, weight increases as well, and vice versa.

For instance, let's calculate the weights of a 10kg object on both Earth and the moon.

Gravitational acceleration on Earth (g₁) = 9.8m/s².

Gravitational acceleration on the moon (g₂) = 1.6m/s².

On Earth:

weight = m × g₁ = 10 × 9.8 = 98 N.

On the moon:

weight = m × g₂ = 10 × 1.6 = 16 N.

From the above example, since the acceleration due to gravity on the moon is 1/6 that of Earth, the weight of a 10kg object on the moon is approximately six times lighter (16 N) than its weight on Earth (98 N).