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Burka
1 month ago
7

Look at the diagram of the moon and three different paths that it could take. A planet with a moon in orbit. The moon has arrows

labeled 1 through 3. 1: Curves up and away from the planet. 2: Moves straight forward. 3: Curves down to follow planet's orbit. Which description applies best to pathway 2? the path of the moon toward the Sun the path of the moon’s orbit around Earth the path the moon would take if it had a larger mass than the Sun the path the moon would take if there was no force of Earth’s gravity
Physics
2 answers:
kicyunya [3.2K]1 month ago
7 0

Answer:

D on edg 2020

Explanation:

Yuliya22 [3.3K]1 month ago
6 0
is 3 and 2

Explanation: the first is 3 while the second is 2.

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A student solving a physics problem for the range of a projectile has obtained the expression r= v20sin(2θ)g where v0=37.2meter/
ValentinkaMS [3465]

The formula for range is:

R = \frac{v_o^2 sin2\theta}{g}

Given values are:

v_0=37.2m/s

where θ equals 14.1 degrees

g=9.80m/s^2

Using the equation above,

R = \frac{37.2^2 sin2*14.1}{9.80}

The calculated range is 66.7 meters.

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5 0
3 months ago
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Can pockets of vacuum persist in an ideal gas? Assume that a room is filled with air at 20∘C and that somehow a small spherical
kicyunya [3294]

Answer:

The time required is 20 μs

Explanation:

Here is the data provided:

temperature = 20°C  = 293 K

radius = 1 cm

atomic mass of air = 29 u

To determine

the duration for air to refill the vacuum space

solution:

We calculate the root mean square velocity of air particles. This can be expressed as:

\frac{1}{2}mv^2 = \frac{3}{2}RT

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v = \sqrt{\frac{3RT}{M} }............................1

v = \sqrt{\frac{3(8.314)293}{29*10{-3}kg} }

Resulting in v = 501.99 m/s.

<pNow, to cover the distance of 1 cm,<pThe duration needed for air is calculated as:

time taken = \frac{r}{v}

which gives us:

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so, time taken = 19.92 × 10^{6} seconds = 20μs.

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3 0
3 months ago
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3 0
2 months ago
a force of 6lbs acts on an object with a weight of 35 lbs on earth. determine the objects acceleration. final answer must be 5.5
kicyunya [3294]
Weight of the object = 35 lbs
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Again applying the same formula,
a = F/m
a= 6/1.09
a= 5.489

Thus, the acceleration is approximately 5.5 ft/s²!!
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2 months ago
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