The mass, m, of the gas amounts to 0.2504 grams. Explanation: First, we need to calculate the cylindrical tube's volume. The formula for the volume of a cylinder is given by; where V indicates volume, π signifies pi, r represents the radius, and h indicates height or length. Given the following parameters: Radius, r = 1.5 cm, Length, h = 14.4 cm, Density, d = 0.00123 g/cm³. Plugging these into the equation, the volume of the cylindrical tube calculates to be 203.6016 cm³. Density can be defined as mass divided by the volume of an object. Simply put, density is mass per unit volume. Mathematically, density is represented by the formula; by substituting into the equation, we conclude that Mass = 0.2504 g.
Answer:
The coefficient of kinetic friction is found to be 0.432.
Explanation:
Comprehensive steps and derivations with necessary substitutions are detailed in the attached document.
We will utilize Wien's displacement law, given by the equation λ T = b, where λ represents the wavelength of emitted light from a heated object at maximum. By substituting the provided temperature and constant b into the equation, we find λ for various temperatures: at 500 K, λ = 5.796 μm or 5796 nm; at 1050 K, λ = 2760 nm; at 1800 K, λ = 1610 nm; and at 2500 K, λ = 1159.2 nm. The visible light spectrum starts at 740 nm, suggesting that at 2500 K, some visible red light may emerge as its calculated peak wavelength is within the visible range.
Answer:
0.000047N
Explanation:
We know that
intensity (I) = P/ A
Where
P= power
A= Area
Thus, the power absorbed can be calculated as:
Power = Intensity x Area
This equals = 1.4 x 10^3 x(10)
Thus,
14000 Watts = 14 kWatt
However, the radiation pressure can be defined as
time-averaged intensity divided by the speed of light in a vacuum
So,
P = (1.4 x 1000)/c
Also,
F= P x A
Thus,
((1.4 x 1000)/(3 x10^8)) x 10
This results in
=0.000046666N
Rounded to two significant figures gives us
=0.000047 N