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Illusion
10 days ago
5

Hawks and gannets soar above the ground and, when they spot prey, they fold their wings and essentially drop like a stone. They

have evolved a highly aerodynamic shape that lets gravity build up their speed without having to make the effort of trying to fly at a high speed (See the figure of a diving hawk below. The technical term for this maneuver is "stooping".) For this problem, you may approximate the strength of the gravitational field as g = 10 N/kg.A. If a hawk is slowly soaring at a height of about 150 meters and spots a vole on the ground, folds its wings and begins its dive, with what speed will it be going when it gets to the ground? It's flight isn't powered: it just falls with an acceleration of ~10 m/s2. (Of course, it has to turn a bit above the ground in order not to crash. We will ignore this part of its flight path.)
Physics
1 answer:
Softa [913]10 days ago
3 0

Answer:

  v = 54.2 m/s

Explanation:

We can utilize conservation of energy to solve this issue.

Initial condition Higher

         Em₀ = U = m g h

Final condition. Lower

        Em_{f} = K = ½ m v²

        Em₀ = Em_{f}

        m g h = ½ m v²

         v² = 2gh

         v = √ (2gh)

Now let's perform the calculation

         v = √ (2 * 9.8 * 150)

         v = 54.2 m/s

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A closed system of mass 10 kg undergoes a process during which there is energy transfer by work from the system of 0.147 kJ per
Softa [913]

Result: -50.005 kJ

Details:

Provided Data

mass of the system = 10 kg

work done = 0.147 kJ/kg

Elevation change (\Delta h)=-50 m

initial speed (v_1)=15 m/s

Final Speed (v_2)=30 m/s

Specific internal Energy (\Delta U)=-5 kJ/kg

according to the first Law of thermodynamics

Q-W=\Delta H

\Delta H=\Delta KE+ \Delta PE +\Delta U

where KE represents kinetic energy

PE indicates potential energy

U denotes internal Energy

\Delta H=\frac{m(v_2^2-v_1^2)}{2}+mg(\Delta h)+\Delta U

Q=W+\Delta KE+ \Delta PE +\Delta U

Q=0.147\times 10+\frac{10\cdot (30^2-15^2)}{2}+10\cdot 9.81\cdot (-5)-5\times 10

Q = 1.47 + 3.375 - 4.850 - 50

Q = -50.005 kJ

5 0
13 days ago
An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista
Sav [1105]

Answer:

        h = 12.8 cm

Explanation:

The initial parameters are as follows:

distance = 6.4 cm

  • when the object descends, its weight matches the spring's force

        weight = spring force

         mg = ky... equation 1

  • potential energy stored in a stretched spring = work done by the spring

        mgh = 0.5 x k x h^{2}....equation 2

  • Substituting from equation 1 into equation 2

                kyh =  0.5 x k x h^{2}

                y =  0.5 x h

                2y = h

  • where y is 6.4, yielding the maximum elongation as

          h = 2 x 6.4 = 12.8 cm

6 0
5 days ago
Can pockets of vacuum persist in an ideal gas? Assume that a room is filled with air at 20∘C and that somehow a small spherical
kicyunya [1025]

Answer:

The time required is 20 μs

Explanation:

Here is the data provided:

temperature = 20°C  = 293 K

radius = 1 cm

atomic mass of air = 29 u

To determine

the duration for air to refill the vacuum space

solution:

We calculate the root mean square velocity of air particles. This can be expressed as:

\frac{1}{2}mv^2 = \frac{3}{2}RT

where m indicates mass, t is temperature, v is speed, and R is the ideal gas constant, which is approximately 8.3145 (kg·m²/s²)/K·mol.

v = \sqrt{\frac{3RT}{M} }............................1

v = \sqrt{\frac{3(8.314)293}{29*10{-3}kg} }

Resulting in v = 501.99 m/s.

<pNow, to cover the distance of 1 cm,<pThe duration needed for air is calculated as:

time taken = \frac{r}{v}

which gives us:

time taken = \frac{1*10^{-2}m}{501.99}

so, time taken = 19.92 × 10^{6} seconds = 20μs.

Thus, the required time is 20 μs.

3 0
10 days ago
A 5.8 × 104-watt elevator motor can lift a total weight of 2.1 × 104 newtons with a maximum constant speed of
Keith_Richards [1034]
Power is defined as the speed at which work is performed on an object. Like all rates, power is measured in relation to time. It reflects how quickly a task is completed. Two identical tasks can be executed at varying speeds - one slower and the other faster. The equation P = Fv can be used, where P symbolizes power, F denotes force, and V represents average velocity. Calculating the average velocity gives us V = P/F, or V = (5.8 x 10^4 W) / (2.1 x 10^4 N), resulting in V = 2.8 m/s.
8 0
10 days ago
You stand on a bathroom scale in a moving elevator. what happens to the scale reading if the cable holding the elevator suddenly
Sav [1105]

A bathroom scale operates under gravitational influence. Typically, a reading is captured when your body applies force onto the scale. Yet in this scenario, as both you and the scale move downwards, your body ceases to press against the scale. Consequently, the result is:

<span>The scale reading will instantly drop to zero</span>

7 0
5 days ago
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