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Artist 52
3 months ago
15

A box of volume V has a movable partition separating it into two compartments. The left compartment contains 3000 particles, the

right one contains 1000 particles, and initially the partition is in the middle so that the compartments are of equal volume. The partition is released and slides horizontally until the system is in a new equilibrium state.
(a) In terms of V, what is the volume of each compartment once the new equilibrium state is reached?
(b) What is the change in the system’s entropy during this process?
Physics
1 answer:
Softa [3K]3 months ago
6 0

Answer:

a) V1 = 4V - V2/3 and V2 = 4V - 3V1

b) Δe = 4000V - 4000V2 + 9000V1

Explanation:

Let V be the volume of the box with two compartments

V1 is for the left compartment

V2 is for the right compartment

Momentum for the compartments before impact:

3000V1 + 1000V2

Momentum after the impact:

V(3000 + 1000) = 4000V

a) To find the volume of each compartment, V1 and V2, we note:

Momentum prior to impact = Momentum post-impact

3000V1 + 1000V2 = 4000V

Thus, V1 = (4000V - 1000V2)/3000 = 4V - V2/3

And V2 = (4000V - 3000V1)/1000 = 4V - 3V1

b) The change in entropy, Δe = 4000V1 - 1000V2

Substituting for V1 and V2 gives:

4000(4V - V2)/3 - 1000(4V - 3V1)

Results in 16000V - 4000V2/3 - 4000V + 3000V1

Finally yielding Δe = 4000V - 4000V2 + 9000V1

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d a and b: it vibrates in both scenarios but differs in whether the sound is audible or not. The absence or presence of molecules does not prevent the tuning fork from vibrating, but it can obstruct hearing, as sound necessitates a mechanical wave medium. This brings us to (c) where the vibrations do occur, but they cannot reach your ears due to the lack of a medium.
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2 months ago
The wavelength of light is 5000 angstrom. Express it in nm and m.
serg [3582]

Answer:

1 angstrom equals 0.1 nm.

To convert 5000 angstroms: 5000 angstrom = 5000 / 1 × 0.1 nm.

= 500 nm

1 \:  angstrom = 1 \times  {10}^{ - 10} m

To express 5000 angstroms in meters: 5000 angstrom = 5000 × 1 × 10^-10.

= 5 × 10^-7 m

Hope this explanation is useful for you.

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4 months ago
The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume tha
Maru [3345]

Answer:

A) 5.1*10^10m B) 5.4*10^6m

Explanation:

Utilizing the formula for surface radiation P (energy per second in Watts) = emissivity constant * surface area * Stefan-Boltzmann constant * Temperature in Kelvin^4 *

2.7*10^31 = 1* 5.67*10^-8*A*11000^4

Rearranging to solve for A = 2.7*10^31 / (5.67*10^-8*1.46*10^16) = 0.3261*10^23m^2

Assuming the shape is spherical, the surface area is = 4πR^2 (radius of Rigel)

R = √(0.3261*10^23 / 4*π) = 5.1 * 10^10m

B) repeating the same calculation

2.1 *10^23 = 1*A*5.67*10^-8*10000^4 where A is the surface area of Procyon

Rearranging gives A = 2.1*10^23/(5.67*10^-8*10^16)

A = 0.37*10^15

Assuming the star is spherical;

A = 4πR^2 where R is Procyon's radius

R = √(0.37*10^15/4π) = 5.4*10^6m

4 0
2 months ago
A charge of uniform volume density (40 nC/m3) fills a cube with 8.0-cm edges. What is the total electric flux through the surfac
Keith_Richards [3271]

Answer:

The flux across the cube's surface is 2.314\ Nm^{2}/C.

Solution:

According to the details provided:

Cube edge length, a = 8.0 cm = 8.0\times 10^{- 2}\ m.

Volume charge density, \rho_{v} = 40 nC/m^{3} = 40\times {- 9}\ C/m^{3}.

Now,

To find the electric flux:

\phi = \frac{q}{\epsilon_{o}}

where

\phi = electric flux

\epsilon_{o} = 8.85\times 10^{- 12}\ F/m = permittivity of vacuum.

The volume charge density for this scenario is described by:

\rho_{v} = \frac{Total\ charge, q}{Volume of cube, V}

Cube volume, V = a^{3}.

Thus,

V = (8.0\times 10^{- 2})^{3} = 5.12\times 10^{- 4}\ m^{3}.

The total charge can be derived from equation (2):

q = \rho_{v}V = 40\times {- 9}\times 5.12\times 10^{- 4}.

q = 2.048\times 10^{-11}\ F = 20.48\ pF.

Now, insert the value of 'q' into equation (1):

\phi = \frac{2.048\times 10^{-11}}{8.85\times 10^{- 12}} = 2.314\ Nm^{2}/C.

5 0
3 months ago
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