Which descriptions from the list below accurately describe the relationship between QRS and TUV

Mel descends 50-35=15 feet in 5-2=3 seconds. Thus, her descent rate is 15/3=5 ft/sec.
Victor descends 60-50=10 feet in 4-1=3 seconds. Hence, his descent rate is 10/3=3⅓ ft/sec. Mel is faster, traveling at 5 ft/sec.

The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>

Answer:

 

Step-by-step explanation:

 

The given formula doesn't appear to match any of the answer choices.

  W = (P/2) - L

Correct question:

An urn holds 3 red and 7 black balls. Players A and B take turns withdrawing balls until a red one is chosen. Calculate the probability that A picks the red ball. (A goes first, followed by B, with no replacement of drawn balls).

Answer:

The likelihood that A picks the red ball is 58.33 %

Step-by-step explanation:

A will select the red ball if it is drawn 1st, 3rd, 5th, or 7th.

1st draw: 9C2

3rd draw: 7C2

5th draw: 5C2

7th draw: 3C2

Calculating for all possible scenarios gives us:

9C2 = (9!) / (7!2!) = 36

7C2 = (7!) / (5!2!) = 21

5C2 = (5!) / (3!2!) = 10

3C2 = (3!) / (2!) = 3

Adding these possibilities results in 36 + 21 + 10 + 3 = 70.

The total outcomes for selecting a red ball = 10C3

10C3 = (10!) / (7!3!)

= 120.

The probability that A selects the red ball is determined by dividing the sum of possible events by the overall outcomes.

P( A selects the red ball) = 70 / 120

= 0.5833

= 58.33 %

1.55 CHF =?1 The price of the watch in Geneva is 1.55 CHF =?1 while 193 CHF =??1, which can be designated as x. Setting up a proportion, we cross-multiply, resulting in 1.55x = 193. Dividing by 1.55, we find x = 124.52 in x units. However, Manchester merchants are pricing it at 143 x units, so the difference is 143 - 124.52 = 18.48 units more expensive in Manchester.