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OleMash
3 days ago
8

During a race the dirt bike was observed to leap up off the small hill at A at an angle of 60^o with the horizontal. If the poin

t of landing is 20 ft away, determine the approximate speed at which the bike was traveling just before it left the ground. Neglect the size of the bike for the calculation.
Physics
1 answer:
Ostrovityanka [2.2K]3 days ago
8 0
The velocity is expressed in feet per second, with the time noted in seconds.
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Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer
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1 month ago
Which statements about inertia and centripetal force are correct? Check all that apply. Inertia is always present. Inertia cause
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Violet light (λ = 400 nm) passing through a diffraction grating for which the slit spacing is 6.0 μm forms a pattern on a screen
Maru [2355]

Answer:

The third-order dark fringe

Explanation:

y = Distance from central bright fringe = 204 mm

λ = Wavelength = 400 nm

L = Distance from screen to source = 1 m

d = Slit spacing = 6 μm

tan\theta =\frac{y}{L}\\\Rightarrow tan\theta =\frac{204}{1000}=0.2012^{\circ}

dsin\theta=m\lambda\\\Rightarrow m=\frac{dsin\theta}{\lambda}\\\Rightarrow m=\frac{6\times 10^{-6}sin0.2012}{400\times 10^{-9}}=2.9982\approx 3

The order of the fringe is 3

Thus, it’s identified as a dark fringe.

3 0
18 days ago
A man makes a 27.0 km trip in 16 minutes. (a.) How far was the trip in miles? (b.) If the speed limit was 55 miles per hour, wa
Maru [2355]

Answer:

(a) 16.777 miles

(b) Yes, he exceeded the speed limit

Explanation:

(a)

We need to perform the necessary calculations to convert kilometers to miles:

27km*\frac{1000m}{1km} *\frac{1mi}{1609.34m} =16.77706389mi

Thus, the distance of the trip in miles is:

d=16.77706389mi

(b)

Next, we will compute the man's speed during the journey:

v=\frac{d}{t}

Before that, we must convert minutes to hours:

16min*\frac{1h}{60min} =2.666666667h

The resulting speed is:

v=\frac{16.77706389mi}{2.666666667h} =62.91398959\frac{mi}{h}

Consequently:

62.91398959\frac{mi}{h}>55\frac{mi}{h}

Thus, it can be concluded that the driver was speeding

8 0
21 day ago
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