The period of a pendulum is the time it takes the pendulum to swing back and forth once. If the only dimensional quantities that
1 answer:
Clarification:
Let T signify the pendulum's period. The time's SI unit is seconds (s).
It is influenced by the length of the pendulum, l, and the gravitational acceleration, g.
The SI units for gravitational acceleration, g, and pendulum length, l, are m/s² and m, respectively.
Dividing m by m/s² produces s². Taking the square root of s² results in s, which is the SI unit for the pendulum's period.
Thus,
This concludes the solution we sought.
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Answer:
The minimum resistance value is
Explanation:
According to the question, we have:
The voltage given as
The internal resistance as
The goal here is to find the minimum resistance for the voltmeter such that its reading is within 1.0% of the battery's emf.
This means we require voltmeter resistance such that:
V = (100% - 1%) of E
Where E is the battery's e.m.f. and V is the voltmeter reading.
So, V = 99% of E = 0.99 E = 7.425.
In general, we have:
E = V + ir
where ir denotes the internal voltage drop across the voltmeter, and V is the reading from the voltmeter.
By rearranging, we get:
Since the current remains constant throughout the circuit:
where is the voltmeter resistance value.
Hence,
Answer: The frequency is 1714.3 Hz
Explanation: The calculation is derived from the Doppler effect formula.
Since the source is approaching the observer, the observer's velocity is considered positive.
Refer to the attached document for the detailed derivation
